All categories

3 years ago

What are the reactant(s) and product(s) of this reaction? Write down the equation, in words, for the formation of rust.

1 answer:

6 0

A fabric store sells two types of ribbon. One customer buys 3 rolls of the lace ribbon and 2 rolls of the satin ribbon and has a total of 120 yards of ribbon. Another customer buys 2 rolls of the lace ribbon and 4 rolls of the satin ribbon and has a total of 160 yards of ribbon.

How many yards are on one roll of lace ribbon and one roll of satin ribbon?

There are 20 yards on one roll of lace ribbon and there are 30 yards on one roll of satin ribbon.
There are 30 yards on one roll of lace ribbon and there are 20 yards on one roll of satin ribbon.
There are 40 yards on one roll of lace ribbon and there are 10 yards on one roll of satin ribbon.
There are 10 yards on one roll of lace ribbon and there are 40 yards on one roll of satin ribbon.

You might be interested in

a uniform beam of length l and mass mb is supported by two pillars located l/3 from either end, as shown in the figure. a duck o

Cloud [144]

When the system is in equilibrium, the sum of the moment about a point is

zero.

$Force \ shown \ by \ the \ scale \ under \ the \ right \ pillar \ is \ F = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}$

Reasons:

Length of the beam = l

Mass of the beam = $m_B$

$Location \ of \ the \ two \ pillars = \dfrac{l}{3} \ from \ either \ end$

Mass of the duck = $m_D$

Required:

Force shown by the scale under the right pillar.

Solution:

The location of the duck = On the left end of the beam

When the system is in equilibrium, we have; ∑M = 0

Taking moment about the left pillar, we get;

Clockwise moment = $m_D \times g \times \dfrac{l}{3} + F \times \dfrac{l}{3}$

Anticlockwise moment = $m_B \times g \times \dfrac{l}{6}$

At equilibrium, clockwise moment = Anticlockwise moment

Therefore;

$m_D \times g \times \dfrac{l}{3} + F \times \dfrac{l}{3} = m_B \times g \times \dfrac{l}{6}$

$F \times \dfrac{l}{3} = m_B \times g \times \dfrac{l}{6} - m_D \times g \times \dfrac{l}{3}$

$F = \dfrac{m_B \times g \times \dfrac{l}{6} - m_D \times g \times \dfrac{l}{3}}{\dfrac{l}{3} } = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}$

$Force \ shown \ by \ the \ scale \ under \ the \ right \ pillar, \ F = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}$

Learn more here:

brainly.com/question/12227548

brainly.com/question/14778371

7 0

3 years ago

Does air defy gravity?

Andreyy89

Answer:

If you were to inject air into space what would have happen?

Explanation:

In order for air to defy gravity, it would require atmospheric pressure. But air dosen't defy gravity unless it has the support of atmospheric pressure.

6 0

3 years ago

Help i hope this actually works

KIM [24]

Answer:

it does tbh.

Explanation:

6 0

3 years ago

A flywheel in the form of a uniformly thick disk of radius 1.33 m1.33 m has a mass of 70.6 kg70.6 kg and spins counterclockwise

ladessa [460]

Answer: