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andrew11 [14]
2 years ago
8

What unit is used to describe volume?

Chemistry
1 answer:
dusya [7]2 years ago
8 0

Answer:

Explanation:

Hello friend!!!!!

here's ur answer

The unit to describe volume is <u><em>cubic meter.</em></u>

Hope this helps

plz mark as brainliest!!!

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63<br> 84/<br> 85<br> 86<br> 87/<br> 88<br> 891<br> 901<br> 911<br> 921
Sergeeva-Olga [200]

Answer: I have no way of answering this ,let alone give you the right answer

Explanation: You din't even tell us what the Q is

5 0
3 years ago
What is indicated by Benedict's solution changing from blue to orange when heated?
Sidana [21]

1.Benedict�s reagent (blue in color):

Benedict's reagent (also called Benedict's solution or Benedict's test) is a reagent named after an American chemist, Stanley Rossiter Benedict. It can be prepared from sodium carbonate, sodium citrate and copper(II) sulfate.

Benedict's reagent is used as a test for the presence of reducing sugars such as glucose, fructose, galactose, lactose and maltose.

In the presence of reducing sugars and heat in water benedict�s reagent will change color from blue to orange/green and sometimes as well orange red.

Benedict's reagent contains blue copper(II) sulfate (CuSO4) which is reduced (takes up lost electrons from the reducing sugar) to a, ORANGE/RED colored red copper(I) oxide (Cu2O) by aldehydes, also oxidizing them to carboxylic acids. The copper(I) oxide is insoluble in water and so precipitates. (wiki sourced).

Summary: benedicts reagent color changes from a blue, to then a green, then final orange red color when electrons from an �unknown� reducing sugar, in a warm water bath suspension.

CLUE: *Benedicts reagent changes color to a Orange/Red color if a reducing sugar is your unknown.

2. Biuret reagent (blue in color normally, unreacted): is made of potassium hydroxide (KOH) and copper (II) sulfate (CuSO4), together with potassium sodium tartrate.

The Biuret blue color (no heat needed) reagent turns Violet in the presence of proteins (also called by some polypeptide chains), and changes to Violet/Pink when combined with short-chain (not long) polypeptides (amin acids {monomers of a protein} linke dtogethe rin a chain by bonds identified as peptide bonds, hence �poly (many) peptides�.

The reagent, Biuret protein assay, is a colorimetric (color change) yest used to determine an unknown solution�s protein concentration.

3.Sudan IV (dark red/burgundy color) is a lysochrome (fat-soluble dye) diazo dye used for staining of lipids, triglycerides and lipoproteins on frozen paraffin sections.

In industry, Sudan IV is used to color nonpolar substances like oils, fats, waxes, greases, various hydrocarbon products, and acrylic emulsions. (wiki sourced). In other words lipids �pick up� the color of the Sudan IV dye.

Scenario:

In a lab room, one (you) is handed three small reagent containers, some beakers, some test tubes, safety gloves and goggles, and SIX unknown solutions in testubes, and a known control of distilled water, all to be tested, by you, with the reagents, for the presence of either MONOSACCHARIDES (reducing sugar varieties), PROTEINS (long or short chain polypeptides) and potential LIPIDS: oils fats and waxes

The six unknowns and distilled water are labeled one, two, three, four, five, six, and seven.

ALL are all clear in color.     Only one of the test tube containers contains pure distilled water.

TEST ONE:

When one uses Benedict�s reagent on samples from each test tube, in a hot water bath heat source: samples ONE and FOUR turn color from Benedict�s blue being added to them, in color, from a blue to green to red-orange color (a color change definitely happens).

Samples TWO, THREE, FIVE, SIX, and, SEVEN change from clear to the Benedict�s reagent blue color when the benedicts was added. In essence NO color change happens with these unknon samples, even in the warm water bath. ONLY ONE and FOUR are positive color changes.

TEST TWO:

When one uses the Biuret reagent on samples from test tubes TWO, and THREE, a Pink color forms, and in sample FIVE the chemical unknown changes to a Violet purple color.

IN Samples   ONE FOUR SIX and SEVEN stay the blue color of the Biuret reagent that was added to the initially clear samples. NO color change occurs in these

TEST THREE:

When one adds Sudan IV to all seven samples ONLY sample SIX reacts and the liquid of the unknown sample becomes a reddish / burgundy color.

Samples ONE, TWO, THREE, FOUR, FIVE, and SEVEN turn color to a dilute red color from the stain added to the clear samples, but not in the intensity that is sample unknown SIX.

What can you deduce for the preceding set of experiments as to what was in each sample regarding: Monosaccharide / reducing sugar, a short chain polypeptide, a long chain polypeptide, or a lipid.  Now you just have to do the samples .

3 0
3 years ago
Read 2 more answers
Create a hypothesis that can be tested in an experiment​
sammy [17]
<h3>Please mark me as Brainliest ........</h3>

8 0
2 years ago
which materials are included in the hydrosphere that are not in liquid form A. ice caps B. lakes and rivers C. rainforest and la
soldi70 [24.7K]

Answer:

The correct answer is option A, that is, ice caps.

Explanation:

The part of the planet Earth covered by water or ice is known as the hydrosphere. It comprises lakes, oceans, rivers, polar ice caps, and glaciers. The polar ice caps and glaciers are the only elements of solid found in the hydrosphere.  

The other options, that is, lakes and rivers are also a part of hydrosphere but they are in liquid form. While rainforest and rocks and minerals are the parts of the lithosphere, not hydrosphere.  

8 0
2 years ago
Read 2 more answers
Calculate how much 95% ethyl alcohol will be required to dissolve 0.1 g of sulfanilamide at 78 c using volume calculate how much
Oduvanchick [21]
According to the source below, the solubility of sulfanilamide in 95% ethyl alcohol at 78°C is 210 mg/mL. Since 0.1 g = 100 mg, we can set up a proportion: 

(210 mg) / (1 mL) = (100 mg) / (x mL) Solving, x = 0.48 mL of 95% ethyl alcohol will be required.


I do not know previously the solubility of sulfanilamide in 95% ethyl alcohol. Let us accept the solubility you quoted here. 

100/210 = 0.47619047619.. ≈ 0.48 (ml) 

at 0C, the amount of sulfanilamide remains in the solution is: 14*(100/210) = 6.67 (mg), since you only have 0.48 ml solution. 

The volume of the solution will change a little by cooling from 78C to 0C. You may also consider this volume change if you have data.
6 0
3 years ago
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