Ka is the equilibrium constant for the ionization for a reaction. It is calculated as follows
ka is equal to (H3o ions)(A-) divided by (HA)
2.00x106i s equal to 0.153x0.153 divided by ( HA)
(2.00x106)HA is equal to 0.023409
HA concentration is therefore equal to 0.023409/2.00x106 which is 1.104x10^-4moles/litre
Business owners must consider the products mission statement, a unique brand, the timing, the packaging, promotion, the audience.
To create a product you first need a problem then a solution. So if the problem is that water bottles aren’t holding enough water, the solution would be to create bigger yet lighter water bottles.
Let’s say you are to create a water bottle that is sturdier than others and can hold more water but weigh less. You would first consider the target audience. People that exercise and are into fitness would find the product more useful. So many making changes to the product to better fit their needs will help. Next the promotion and timing . It would be best to release the product near New Years since that’s when most people go to gyms. This will allow your product to reach a greater target audience and have more sales. Also testing your bottle to make sure it’s up to what you’re proving and so on.
Answer: The boiling point of kerosene ranges from around 150 to 300 degrees Celsius normally being closer to 300 degrees Celsius.
Explanation:
Answer:
Activation energy of phenylalanine-proline peptide is 66 kJ/mol.
Explanation:
According to Arrhenius equation- 
, where k is rate constant, A is pre-exponential factor, 
is activation energy, R is gas constant and T is temperature in kelvin scale.
As A is identical for both peptide therefore-
![\frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_%7Bala-pro%7D%7D%7Bk_%7Bphe-pro%7D%7D%3De%5E%5Cfrac%7B%5BE_%7Ba%7D%5E%7Bphe-pro%7D-E_%7Ba%7D%5E%7Bala-pro%7D%5D%7D%7BRT%7D)
Here 
, T = 298 K , R = 8.314 J/(mol.K) and 
So, ![\frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}](https://tex.z-dn.net/?f=%5Cfrac%7B0.05%7D%7B0.005%7D%3De%5E%7B%5Cfrac%7B%5BE_%7Ba%7D%5E%7Bphe-pro%7D-%2860000J%2Fmol%29%5D%7D%7B8.314J.mol%5E%7B-1%7D.K%5E%7B-1%7D%5Ctimes%20298K%7D%7D)
(rounded off to two significant digit)
So, activation energy of phenylalanine-proline peptide is 66 kJ/mol
Iodine Strontium Silver...... ..I think.
