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3 years ago

1. The Sun orbits the center of the Milky Way. True False

Physics

2 answers:

katrin [286]3 years ago

8 0

Answer: True

Explanation:

Rudiy273 years ago

6 0

Answer:true

Explanation:

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Why do scientists not use US customary units when reporting their data?

Marianna [84]

From britaññica it said time and money. They didn’t have either to switch over from the industrial period and never did. Also from my own person reasoning i think most of the world uses not US customary, so to make stuff more accessible. hope this helps!

8 0

3 years ago

One kind of baseball pitching machine works by rotating light and stiff rigid rod about a horizontal axis until the ball is movi

erastova [34]

Answer:

(a). The ball's centripetal acceleration is $16.17\times10^{2}\ m/s^2$

(b). The magnitude of the net force is 232.9 N.

Explanation:

Given that,

Mass of baseball = 144 g

Speed = 81 mph = 36.2 m/s

Distance = 81 cm

(a). We need top calculate the ball's centripetal acceleration just before it is released

Using formula of centripetal acceleration

$a=\dfrac{v^2}{r}$

Where, v = speed

r = radius

Put the value into the formula

$a=\dfrac{(36.2)^2}{81\times10^{-2}}$

$a=1617.82\ m/s^2$

$a=16.17\times10^{2}\ m/s^2$

(b). We need to calculate the magnitude of the net force that is acting on the ball just before it is released

Using formula of force

$F=\dfrac{mv^2}{r}$

Put the value into the formula

$F=\dfrac{144\times10^{-3}\times(36.2)^2}{81\times10^{-2}}$

$F=232.9\ N$

Hence, (a). The ball's centripetal acceleration is $16.17\times10^{2}\ m/s^2$

(b). The magnitude of the net force is 232.9 N.

4 0

3 years ago

Bumper car A (281 kg) moving

solmaris [256]

use consevation of linear momentum

m1v1+m2v2=(M1+M2)V3
281(2.82)+209(-1.72)=(209+281)V2
792.42-359.48=490v3
432.9=490v3
V3=0.88m/s

4 0

2 years ago

A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?

Kobotan [32]

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

5 0

3 years ago

The electric potential difference between the ground and a cloud in a particular thunderstorm is 2.5 × 109 V. What is the magnit

muminat

Answer:

U = - 4 x $10^{-10}$

Explanation:

ΔV = potential difference = $2.5 * 10^9$ Volts

q = charge on electron = $-1.6 * 10^{-19}$ C

electric potential energy is given as

U = q ΔV = ( $-1.6 * 10^{-19}$ ) ( $2.5 * 10^9$ )

= - 4 x $10^{-10}$

6 0

3 years ago