Answer:
magnitude = 3
unit vector = 
Explanation:
Given vectors:
u = 2i + 2j - k
v = -i + k = -i + 0j + k
(a) u x v is the cross product of u and v, and is given by;
u x v = i(2+0) - j(2 - 1) + k(0 - 2)
u x v = 2i - j - 2k
Now the magnitude of u x v is calculated as follows:
| u x v | = 
| u x v | = 
| u x v | = 
| u x v | = 3
Therefore, the magnitude of u x v is 3
(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e
û =
u x v = 2i - j - 2k [<em>calculated in (a) above</em>]
|u x v| = 3 [<em>calculated in (a) above</em>]
∴ û = 
∴ û = 
Answer : The weight of the car is 9800 N
Explanation :
It is given that,
The mass of the car, m = 1000 kg
We have to find the weight of the car. The weight of an object is defined as the force acting on it under the action of gravity. The mass of an object is the amount of matter present in it.
Using second law of motion :
W = m g
Where
m is the mass of the car
g is the acceleration due to gravity g = 9.8 N/kg
W = 1000 kg × 9.8 N/kg
W = 9800 N
So, the weight of the car is 9800 N.
Hence, this is the required solution.
An approximation used to measure building height is 10 feet per building level.
Converting from feet to meters using the equation:
1 ft = 0.3048m
10 ft = 3.048m
Multiplying that by 30 storeys, we get:
3 x 3.048m = 91.44m, which is near the answer of (3) 10^2 m or 100m.
Answer:
<h2>In a vacuum, light travels at 670,616,629 mph (1,079,252,849 km/h). To find the distance of a light-year, you multiply this speed by the number of hours in a year (8,766). The result: One light-year equals 5,878,625,370,000 miles (9.5 trillion km).</h2>
1 mile = 1609.344 meters 1 hour = 3600 seconds Initial speed of the getaway car = v1 = 0 m/s (At rest) Speed at which the getaway car explodes = v2 = 120 mph = 120 x (1609.344/3600) m/s = 53.…