This is an exercise in the general or combined gas law.
To start solving this exercise, we must obtain the following data:
<h3>Data:</h3>
- V₁ = 4.5 l
- T₁ = 33 °C + 273 = 306 k
- P₁ = 6.54 atm
- T₂ = 94 °C + 273 = 367 k
- V₂ = 2.3 l
- P₂ = ¿?
We use the following formula:
- P₁V₁T₂ = P₂V₂T₁ ⇒ General Formula
Where
- P₁ = Initial pressure
- V₁ = Initial volume
- T₂ = Initial temperature
- P₂ = Final pressure
- V₂ = Final volume
- T₁ = Initial temperature
We clear the general formula for the final pressure.
We solve by substituting our data in the formula:
If I raise the temperature to 94°C and decrease the volume to 2.3 liters, the pressure of the gas will be 15,346 atm.
Answer:
The rate of the reaction increased by a factor of 1012.32
Explanation:
Applying Arrhenius equation
ln(k₂/k₁) = Ea/R(1/T₁ - 1/T₂)
where;
k₂/k₁ is the ratio of the rates which is the factor
Ea is the activation energy = 274 kJ/mol.
T₁ is the initial temperature = 231⁰C = 504 k
T₂ is the final temperature = 293⁰C = 566 k
R is gas constant = 8.314 J/Kmol
Substituting this values into the equation above;
ln(k₂/k₁) = 274000/8.314(1/504 - 1/566)
ln(k₂/k₁) = 32956.4589 (0.00198-0.00177)
ln(k₂/k₁) = 6.92
k₂/k₁ = exp(6.92)
k₂/k₁ = 1012.32
The rate of the reaction increased by 1012.32
Answer:
Explanation:
Cobalt bromate is the name of this compound
It is Hexane: C6H14
Hexane is a colorless liquid that is made from crude oil.
