Whats the correct order of these?

Chemistry

1 answer:

Igoryamba3 years ago

3 0

1109, 5.9 * 10 squared, -0.041, -4.2 times 10 to the -3, and -7.6 times 10 to the -5
Hope this helps

You might be interested in

How to turn any drink into a gummy

Alika [10]

Add gelatin and let it boil, then put it in the freezer for 30 minuets

5 0

3 years ago

What is the maximum number of grams of PH3 that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form PH3

kvv77 [185]

Answer:

6.79 g of phosphine can be produced

Explanation:

The reaction is this:

3H₂ + 2P → 2PH₃

We have the mass of the two reactants, so let's find out the limiting reactant, so we can work with the equation. Firstly, we convert the mass to moles (mass / molar mass)

6.2 g / 30.97 g/mol = 0.200 moles of P

4g / 2 g/mol = 2 moles of H₂

Ratio is 3:2.

3 moles of hydrogen react with 2 moles of P

Then, 2 moles of H₂ would react with (2 . 2)/ 3 = 1.3 moles of P.

We have only 0.2 moles of P, so clearly the phosphorous is the limiting reactant.

Ratio is 2:2. So 2 moles of P can produce 2 moles of phosphine. Therefore, 0.2 moles of P must produce the same amount of phosphine.

Let's convert the moles to mass ( mol . molar mass)

0.2 mol . 33.97 g/mol = 6.79 g

3 0

3 years ago

What heat is liberated in the formation of 10.0 grams of sulfur hexafluoride, SF6, from the elements sulfur and fluorine?

tensa zangetsu [6.8K]

Answer:

$Q=-76.7kJ$

Explanation:

Hello,

In this case, for such formation of sulfur hexafluoride, the standard enthalpy of formation is -1220.47 kJ/mol (data extracted from NIST database). Next, we compute the moles in 10.0 grams of sulfur hexafluoride as shown below:

$n_{SF_6}=10.0gSF_6*\frac{1molSF_6}{146.06 gSF_6}=0.0685mol$