Answer:
8.72 × 10^5 moles
Explanation:
To find the number of moles in 5.25 x 10^29 molecules of sucrose, we divide the number of molecules by Avagadro constant (6.02 × 10²³ molecules). That is;
no. of moles = no. of molecules ÷ 6.02 × 10²³ molecules
In this case of sucrose, no of moles contained is as follows;
5.25 × 10^29 ÷ 6.02 × 10²³
5.25/6.02 × 10^ (29-23)
0.872 × 10^6
= 8.72 × 10^5 moles
Answer:
Climatic condition in coastal regions is milder than the climatic conditions in the continental regions.
Explanation:
Climate in coastal regions is mild. It has both hot summers and winters accompanied by sea breezes. Precipitation and humidity is high in coastal areas. Both the summers and winters have a mild temperature range.
While in continental regions both summer and winters undergo extreme conditions. Summers are extremely hot and winters are extremely cold. They have wide range of climatic exposures such as rainy season, autumn season and spring season in between summer and winter season.
Answer:
37.3
263.5
Explanation:
The scale measures hundreds of units, tens of units, units, and parts of units (1 decimal place.
Scale 1
Hundreds 0 * 100 = 0
Tens: 3 * 10 = 30
Units: 7 * 1 = 7
1/10 unit = 3* 0.1 = 0.3
Total 30 + 7 + 0.3 = 37.3
Scale 2
Hundreds 2 * 100 = 200
Tens: 6 * 10 = 60
Units: 3 * 1 = 3
1/10 unit = 5* 0.1 = 0.5
Total = 200 + 60 + 3 + 0.5 = 263.5
Answer:
Michaelis constant is known as km which is the substrate concentration that encourages the compound to work at half maximum velocity represented by Vmax/2. Michaelis constant is inversely related to the substrate and the affinity of the enzyme.
Induced fit model: The premise of the purported induced fit hypothesis, which expresses that the attachment or association of a substrate or some other atom to an enzyme causes an adjustment to the enzyme in order to fit or restrain its activity.
In substrate, analog Km or Michaelis constant will be high as the substrate will stay because of analogs inhibit activity.
In the transitional state, analog Km will be in the middle of the substrate and product analogs. Progress state analogs are synthetic mixes with a structure catalyzed reaction that looks like the progressing condition of a substrate atom in a compound enzyme.
In item simple thus Km is the least.
0.0013 M = product ananlog,
0.025 M=Transition state, and
0.0045 M = Substrate analog
