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Olegator [25]
3 years ago
8

Lucas is making accessories for the soccer team. He uses 665.72 inches of fabric on headbands for 32 players and 2 coaches. He a

lso uses 286.08 inches of fabric on wristbands for just the players. How much fabric was used on a headband and wristband for each player?
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
3 0

Answer:

Step-by-step explanation:

We have been given that Lucas is making accessories for the soccer team. He uses 665.72 inches of fabric on headbands for 32 players and 2 coaches. He also uses 286.08 inches of fabric on wristbands for just the players.    

First of all, we will find fabric used on headbands for each person by dividing total fabric by total number of persons.

\text{Fabric used on headbands for each person}=\frac{665.72}{32+2}

\text{Fabric used on headbands for each person}=\frac{665.72}{34}

\text{Fabric used on headbands for each person}=19.58

Therefore, 19.58 inches of fabric is used on headbands for each player or coach.  

We are also told that Lucas also uses 286.08 inches of fabric on wristbands for just the players. To find amount of fabric used for wristband of each player, we will divide 286.08 inches of fabric by number of players only.

\text{Fabric used on wristband of each player}=\frac{286.08}{32}

\text{Fabric used on wristband of each player}=8.94

Therefore, 8.94 inches of fabric is used on wristbands for each player.

Now we will add 19.58 inches and 8.94 to find inches of fabric used on a headband and wristband for each player.

\text{Fabric used on a headband and wristband for each player}=19.58+8.94

\text{Fabric used on a headband and wristband for each player}=28.52

Therefore, 28.52 inches of fabric was used on a headband and wristband for each player.

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3 years ago
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Answer:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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For this problem, we have that:

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The lower limit of this interval is:

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The upper limit of this interval is:

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3 years ago
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Answer:

x=133 y=-25

Step-by-step explanation:

I'll do both ways for you. So let's start with Substitution:

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Solve for x.

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Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:

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