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Viktor [21]
3 years ago
15

Explain how an ionic compound forms between Na & N.

Chemistry
1 answer:
maxonik [38]3 years ago
5 0

Answer:

Three Na atom(s) each lose one electron, forming three Na+ ions. One N atom gains three electrons, forming a N^-3 ion. The ions attract, forming Na3N

Explanation:

Three Na atom(s) each lose one electron, forming three Na+ ions. One N atom gains three electrons, forming a N^-3 ion. The ions attract, forming Na3N.

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Na₃N is ionic compound. The electronegativity of is 3.04 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the nitrogen. Sodium becomes positive and nitrogen becomes negative ion.

One nitrogen atom required three electrons to complete the octet while sodium have one valance electron that's why three sodium atoms combine with one nitrogen atom.

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Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We do as follows:

10 mol NH3 ( 6.022 x 10^23 molecules / 1 mol ) = 6.022x10^24 molecules NH3
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Summarize the characteristics of each type of element below
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Answer:

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Why do you think moles are important for stoichiometry?
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(a) ions in a certain volume of .20M NaCl (aq) are represented in the box above on the left. in the box above on the right, draw
mamaluj [8]

Answer:

  • The first picture attached is the diagram that accompanies the question.

  • The<u> second picture attached</u> is the diagram with the answer.

Explanation:

In the box on the left there are 8  Cl⁻ ions and 8 Na⁺ ions.

The dissociaton equation for NaCl(aq) is:

  • NaCl (aq) → Na⁺ (aq) + Cl⁻(aq)

The dissociation equation for CaCl₂ (aq)  is:

  • CaCl₂ (aq) → Ca²⁺ (aq) + 2Cl⁻(aq)

A 0.10MCaCl₂ (aq) solution will have half the number of CaCl₂ units as the number of NaCl units in a 0.20M NaCl (aq) solution.

Thus, while the 0.20M NaCl (aq) solution yields 8 ions of Na⁺ and 8 ions of Cl⁻, the 0.10MCaCl₂ (aq) solution will yield 4 ions of Ca²⁺ (half because the concentration if half)  and 8 ions of Cl⁻ (first take half and then multiply by 2 because the dissociation reaction).

Thus, your drawing must show 4 dots representing Ca²⁺ ions and 8 dots representing Cl⁻ ions in the box on the right.

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