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SpyIntel [72]
2 years ago
12

HELP. ME!!!!!!!!!!!!!!!

Chemistry
2 answers:
Nastasia [14]2 years ago
7 0
It is CO2 because the oxygen compounds is 2 out of three.
Dmitry [639]2 years ago
4 0
A)CO2!! Hope this helps
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First, I would balance the chemical equation.
andrezito [222]
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5 0
3 years ago
Read 2 more answers
How many moles of carbon in 6.64 moles of CCl2 F
Bad White [126]

Answer: 6.64 moles of carbon.

Explanation:

Given data:

Number  of moles of C = ?

Number of moles of CCl₂F₂ = 6.64 mol

Solution:

In one mole of CCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.

In 6.6 moles of CCl₂F₂ :

Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.

Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine

Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine

Read more on Brainly.com - brainly.com/question/15602143#readmore

3 0
3 years ago
In the Bohr model, ____ electrons fill the first energy level, ____ electrons fill the second energy level, and ___ electrons fi
Setler [38]
The answer is d Thus, the first energy level holds 2 * 1^2 = 2 electrons, while the second holds 2 * 2^2 = 8 electrons. Each orbital. The third energy level can hold up to 18 electrons, meaning that it is not full when it has only electrons.
8 0
2 years ago
Alka-Seltzer is a solid mixture of two substances, sodium bicarbonate (NaHCO3) and citric acid (H3C6H5O7). The substances react
laiz [17]

1) List the reactants: sodium bicarbonate (NaHCO₃) and citric acid (H₃C₆H₅O₇).

Reactants undergo change during a chemical reaction.

2) List the products: water (H₂O), carbon dioxide (CO₂) and sodium citrate (Na₃C₆H₅O₇).

Products are the substances formed from chemical reactions.

3) The balanced chemical equation:

3NaHCO₃ + H₃C₆H₅O₇ → 3H₂O + 3CO₂ + Na₃C₆H₅O₇.

6 0
3 years ago
You are performing a titration of a triprotic acid, when you spill water on your lab notebook. you can read that: pka 1 = 1.40,
eimsori [14]
According to the PH formula:
PH= Pka +㏒ [strong base/weak acid]
when we have PH at the first equivalence =3.35 and the Pka1 = 1.4
So, by substitution, we can get the value of ㏒[strong base / weak acid]
3.35 = 1.4 + ㏒[strong base/ weak acid]
∴㏒[strong base/weak acid] = 3.35-1.4 = 1.95 
to get the Pka2 we will substitute with the value of ㏒[strong base/ weak acid] and the value of PH of the second equivalence point
∴Pk2 = PH2 - ㏒[strong base/ weak acid]
          = 7.55 - 1.95 = 5.6 
5 0
3 years ago
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