Question

A 4.0 kg bird has 8.0 joules of kinetic energy how fast is it flying

Answer 1

Answer

The velocity of the bird is 2 m /sec .

Explanation:

The formula for kinetic energy is given by.

$Kinetic\ energy = \frac{1}{2}\ m\ v^{2}$

Where m is mass ,  v is the velocity .

As given

A 4.0 kg bird has 8.0 joules of kinetic energy .

m = 4.0 kg

K.E =  8.0 joules

Putting in the formula

$8.0 = \frac{1}{2}\times 4.0\times v^{2}$

$v^{2}= \frac{8.0\times 2}{4.0}$

$v^{2}= 2\times 2$

$v^{2}= 4$

$\sqrt{4} = 2$

Thus

v = 2 m/sec

Therefore the velocity of the bird is 2 m /sec .