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FrozenT [24]
2 years ago
6

Helpppp!!!

Physics
1 answer:
Korvikt [17]2 years ago
5 0

Answer:

A) 0.25 Hz

B) 6 m

C) 1.5 m/s

Explanation:

The number of waves that pass a certain spot every 20 seconds = 5 waves

The distance between the crest = 6 m

A) The frequency of the wave, f = The number of cycles per second = 5/20 = 0.25 per second = 0.25 Hz

B) The wavelength of the wave, λ = The distance between crests = 6 m

C) The velocity of the wave, v = f × λ = 0.25/s × 6 m = 1.5 m/s.

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Frequency = 1 / (10 seconds) = (1/10) ( / second) = 0.1 per second = <em>0.1 Hz</em>.


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Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

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Using formula of wavelength

\lambda=\dfrac{c}{f}

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Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

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d =\dfrac{m\times\lambda}{\sin\theta}

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d = distance between the two slits

Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

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