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FrozenT [24]
2 years ago
6

Helpppp!!!

Physics
1 answer:
Korvikt [17]2 years ago
5 0

Answer:

A) 0.25 Hz

B) 6 m

C) 1.5 m/s

Explanation:

The number of waves that pass a certain spot every 20 seconds = 5 waves

The distance between the crest = 6 m

A) The frequency of the wave, f = The number of cycles per second = 5/20 = 0.25 per second = 0.25 Hz

B) The wavelength of the wave, λ = The distance between crests = 6 m

C) The velocity of the wave, v = f × λ = 0.25/s × 6 m = 1.5 m/s.

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Answer:

0.31 m

Explanation:

m = mass of the block = 1.5 kg

H = height from which the block is released on ramp = 0.81 m

k = spring constant of the spring = 250 N/m

x = maximum compression of the spring

using conservation of energy

Spring potential energy gained by spring = Potential energy lost by block

(0.5) k x² = mgH

(0.5) (250) x² = (1.5) (9.8) (0.81)

x = 0.31 m

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3 years ago
Although all sports require a person to be in shape to some degree, some sports demand more from the body. Which sport does not
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Answer:

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3 years ago
Read 2 more answers
The suspension system of a 2100 kg automobile "sags" 8.5 cm when the chassis is placed on it. Also, the oscillation amplitude de
Gennadij [26K]

Answer:

Part a)

k = 6.06 \times 10^4 N/m

Part b)

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Explanation:

Part a)

as the mass of the suspension system is given as

m = 2100 kg

also we have

x = 8.5 cm

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mg = kx

(525)(9.81) = k(0.085)

k = 6.06 \times 10^4 N/m

Part b)

Now we know that amplitude decreases by 63% in each cycle

so after one cycle the amplitude will become 37% of initial amplitude

so it is given as

A = 0.37 A_o

also we know

A = A_o e^{-bt/2m}

0.37 A_o = A_o e^{-bt/2m}

\frac{bt}{2m} = 1

b = \frac{2m}{t}

here t = time period of one oscillation

so it is

t = 2\pi\sqrt{\frac{m}{k}}

t = 2\pi\sqrt{\frac{525}{6.06 \times 10^4}}

t = 0.58 s

now damping constant is

b = \frac{2(525)}{0.58}

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7 0
3 years ago
What’s the answer please?
photoshop1234 [79]

Answer:

C

Explanation:

Hope this helps!

8 0
3 years ago
In an oil drop experiment, a drop with a weight of 1.9 x 10-14 N was suspended when the potential difference between 2 plates th
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Answer:

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