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Answer:
1/9
Explanation:
<em>Newton’s Law of Universal Gravitation </em>
Objects with mass feel an attractive force that is proportional to their masses and inversely proportional to the square of the distance.
F = GMm/r²
where
F - the gravitatioal force in Newtons,
M and m -two masses in kilograms
r - the separation in meters.
G - the gravitational constant (6.674*10 ⁻¹¹ N (m/kg) ² )
Because of the magnitude of G , gravitational force is very small unless large masses are involved.
So according to above equation , when the masses are not changing , force is inversely propotional to the square of distance
F1 ∝ 1/r² ---------------(1)
F2 ∝ 1(3r)²
F2 ∝ 1/9r²--------------(2)
(2)/(1)
From their you get as the distance tripled, Force reduce by a factor of 9(3³)
for example , assume the distance get doubled ,Force reduce by a factor of 4 (2²)
<h2>Given that,</h2>
Mass of two bumper cars, m₁ = m₂ = 125 kg
Initial speed of car X is, u₁ = 10 m/s
Initial speed of car Z is, u₂ = -12 m/s
Final speed of car Z, v₂ = 10 m/s
We need to find the final speed of car X after the collision. Let v₁ is its final speed. Using the conservation of momentum to find it as follows :
v₁ is the final speed of car X.
So, car X will move with a velocity of -12 m/s.