Question

A straight wire in a magnetic field experiences a force of 0.026 N when the current in the wire is 1.5 A. The current in the wire is changed, and the wire experiences a force of 0.063 N as a result. What is the new current

Answer 1

Answer:

the new current on the wire is 3.64 A.

Explanation:

Given;

first force on the wire, F₁ = 0.026 N

second force on the wire, F₂ = 0.063 N

first current on the wire, I₁ = 1.5 A

second current on the wire, I₂ = ?

The force on a current carrying conductor placed in a magnetic field is given as;

$F = BIL(sin \theta)$

F ∝ I

$\frac{F_1}{I_1} = \frac{F_2}{I_2} \\\\I_2 = \frac{F_2I_1}{F_1} \\\\I_2 = \frac{0.063\ \times\ 1.5 }{0.026} \\\\I_2 = 3.64 \ A$

Therefore, the new current on the wire is 3.64 A.