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solniwko [45]
3 years ago
7

A straight wire in a magnetic field experiences a force of 0.026 N when the current in the wire is 1.5 A. The current in the wir

e is changed, and the wire experiences a force of 0.063 N as a result. What is the new current
Physics
1 answer:
Marianna [84]3 years ago
5 0

Answer:

the new current on the wire is 3.64 A.

Explanation:

Given;

first force on the wire, F₁ = 0.026 N

second force on the wire, F₂ = 0.063 N

first current on the wire, I₁ = 1.5 A

second current on the wire, I₂ = ?

The force on a current carrying conductor placed in a magnetic field is given as;

F = BIL(sin \theta)\\\\

F ∝ I

\frac{F_1}{I_1} = \frac{F_2}{I_2} \\\\I_2 = \frac{F_2I_1}{F_1} \\\\I_2 = \frac{0.063\ \times\ 1.5 }{0.026} \\\\I_2 = 3.64 \ A

Therefore, the new current on the wire is 3.64 A.

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a)  V = k 2π σ (√(b² + x²) - √ (a² + x²)) ,  

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        E = - k 2π σ x (1 /√(b² + x²) - 1 /√(a² + x²))

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