Answer:
38.5° north of east
Explanation:
Directly northwest is 135° from east. If we say east is +x and north is +y, then the components of the acceleration are:
ax = 2.88 cos 135° ≈ -2.036 m/s²
ay = 2.88 sin 135° ≈ 2.036 m/s²
And the initial velocity is:
v₀x = 115 m/s
v₀y = 0 m/s
After, 25.0 seconds, the final velocity components are:
vx = at + v₀x
vx = (-2.036)(25.0) + 115
vx ≈ 64.1 m/s
vy = at + v₀y
vy = (2.036)(25.0) + 0
vy ≈ 50.9 m/s
The plane's direction is:
θ = atan(vy / vx)
θ = atan(50.9 / 64.1)
θ ≈ 38.5°
The direction of the plane's velocity is approximately 38.5° north of east.
