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REY [17]
3 years ago
10

A plane is flying east at 115 m/s. The wind accelerates it at 2.88 m/s^2 directly northwest. After 25.0 seconds what is the dire

ction of the velocity of the plane?
Physics
1 answer:
Furkat [3]3 years ago
7 0

Answer:

38.5° north of east

Explanation:

Directly northwest is 135° from east.  If we say east is +x and north is +y, then the components of the acceleration are:

ax = 2.88 cos 135° ≈ -2.036 m/s²

ay = 2.88 sin 135° ≈ 2.036 m/s²

And the initial velocity is:

v₀x = 115 m/s

v₀y = 0 m/s

After, 25.0 seconds, the final velocity components are:

vx = at + v₀x

vx = (-2.036)(25.0) + 115

vx ≈ 64.1 m/s

vy = at + v₀y

vy = (2.036)(25.0) + 0

vy ≈ 50.9 m/s

The plane's direction is:

θ = atan(vy / vx)

θ = atan(50.9 / 64.1)

θ ≈ 38.5°

The direction of the plane's velocity is approximately 38.5° north of east.

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Answer:

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Explanation:

Given data

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Answer:

Explanation:

Given

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3 years ago
What is the resistance ofa wire made of a material with resistivity of 3.2 x 10^-8 Ω.m if its length is 2.5 m and its diameter i
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R = 0.407Ω.

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To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.

We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4.  Then:

R =[(3.2x10⁻⁸Ω.m)(2.5m)]/[π(0.5x10⁻³m)²/4]

R = 8x10⁻⁸Ω.m²/1.96x10⁻⁷m²

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