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seropon [69]
3 years ago
7

A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution? Useful formulas..

Chemistry
2 answers:
max2010maxim [7]3 years ago
7 0
They are asking you for OH- ions concentration, which is why you have to find the pOH of the solution. You can easily do this with this formula:

pH + pOH = 14

Solve for pOH and you get:

pOH = 14 - pH

Replace the pH with it's value:

pOH = 14 - 11.8
pOH = 2.2

Now that you have the pOH you can find the concentration of OH- ions with this formula:

pOH = -log[OH-]

Solve the formula for [OH-] and you get:

[OH-] = 10^(-pOH)

Now replace pOH with it's value:

[OH-] = 10^(-2.2)
[OH-] = 0.006309 M

The concentration of OH- atoms is 0.006309M or in the scientific notation 6.309×10^(-3)M
olya-2409 [2.1K]3 years ago
3 0

Answer:

Its B

Explanation:

Took the test on E D G E

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The empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

<h3>How to calculate empirical formula?</h3>

The empirical formula of a compound is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of the given compound can be calculated as follows:

  • Hafnium = 55.7% = 55.7g
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First, we convert mass values to moles by dividing by the molar mass of each element

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Next, we divide each mole value by the smallest

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Therefore, the empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

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