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3 years ago

A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution? Useful formulas..

2 answers:

max2010maxim [7]3 years ago

7 0

They are asking you for OH- ions concentration, which is why you have to find the pOH of the solution. You can easily do this with this formula:

pH + pOH = 14

Solve for pOH and you get:

pOH = 14 - pH

Replace the pH with it's value:

pOH = 14 - 11.8
pOH = 2.2

Now that you have the pOH you can find the concentration of OH- ions with this formula:

pOH = -log[OH-]

Solve the formula for [OH-] and you get:

[OH-] = 10^(-pOH)

Now replace pOH with it's value:

[OH-] = 10^(-2.2)
[OH-] = 0.006309 M

The concentration of OH- atoms is 0.006309M or in the scientific notation 6.309×10^(-3)M

olya-2409 [2.1K]3 years ago

3 0

Answer:

Its B

Explanation:

Took the test on E D G E

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<u>Answer:</u> The volume of permanganate ion (potassium permanganate) is 10.0 mL

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5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

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$0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL$

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