Lamina and turbulent flow
Explanation:
mentioning about lamina and turbulent flow we could say that both form in different period of time
Im confused bc im not sure if this is a full question
Answer:
Explanation:
We know that the formula for acceleration is given by:
, where v = Final velocity
u= Initial velocity
Given : The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration.
i.e. u= 110 km/h
[∵ 1 km= 100 meters and 1 hour = 3600 seconds]
v= 0 m/s ( At brake , final velocity becomes 0)
t=4.5 seconds
Substitute all the values in the formula , we get

Hence, the average acceleration of the car during braking is
.
B will be your answer hope this helped
r₁ = distance of point A from charge q₁ = 0.13 m
r₂ = distance of point A from charge q₂ = 0.24 m
r₃ = distance of point A from charge q₃ = 0.13 m
Electric field by charge q₁ at A is given as
E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C towards right
Electric field by charge q₂ at A is given as
E₂ = k q₂ /r₂² = (9 x 10⁹) (4.50 x 10⁻¹²)/(0.24)² = 0.703 N/C towards left
Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction
Electric field at A will be zero when
E₁ = E₂ + E₃
1.225 = 0.703 + E₃
E₃ = 0.522 N/C
Electric field by charge "q₃" is given as
E₃ = k q₃ /r₃²
0.522 = (9 x 10⁹) q₃/(0.13)²
q₃ = 0.980 x 10⁻¹² C = 0.980 pC