Answer:
Explanation:
Speed of an object is defined as the ratio of the distance covered by the object to the time taken to cover that distance.
Let
be the speed of the object.
Let
be the distance travelled by the object.
Let
be the time taken by the object.
So,
s=
So,the speed of the car is 
To choose the correct box plot, verify each of the options and make sure all the values in the plot match the values provided.
<h3>How to identify the median?</h3>
In a box plot, this value is represented by a vertical line located in the middle of the graph.
<h3>How to identify the maximum and the minimum?</h3>
The maximum is the value located on the farthest right, while the minimum is located on the farthest left.
<h3>How to identify the quartiles?</h3>
Divide the graph into 4 and analyze how much each quartile represents.
Learn more about graphs in: brainly.com/question/16608196
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Answer:
(b) In ideal condition we neglect mass of spring but in real springs mass of spring adds another factor to its time period.
since we are adding a factor of mass to the system, and frequency being inversely proportional to squared root of mass, we can come to a general conclusion that it effectively reduces the natural frequency .
Explanation:
kindly check the attachment for explanation.
Weight equals mass*gravity
W = mg
Given m = 3.1 kg, g = 9.8 m/s^2
W = (3.1)(9.8)
W = 30.38
I'm not 100% sure but I think the answer is 60.4, because you multiply 3.20 by 10, to get 32 - 9 = 23, then subtract 23 from 83.4. Hope this helps you, and good luck!!!