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natta225 [31]
3 years ago
5

In which direction is there a net force of 200 N?

Physics
2 answers:
hram777 [196]3 years ago
4 0

Answer:

right    

Explanation:

The up and down forces cancel

  then you are left with a    -200    and a  + 400

     resulting in a + 200   (to the right)

sweet [91]3 years ago
3 0

Answer:

It's Left

Explanation:

have a nice day!! :D

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The kinetic energy of an object increases as its ____ its potential energy
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The kinetic energy of an object increases as its decreases <span>its potential energy as the sum of energy will remain constant.

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8 0
3 years ago
A cannon, positioned on a hill, shoots a cannonball horizontally at 23 m/s. The cannonball hits the stone wall 1.96 m below the
irina [24]

Answer: 14. 49 m

Explanation:

We can solve this problem with the following equations:

x=V_{o} cos \theta t (1)

y-y_{o}=V_{o} sin \theta t-\frac{1}{2}gt^{2} (2)

Where:

x is the horizontal distance between the cannon and the ball

V_{o}=23 m/s is the cannonball initial velocity

\theta=0\° since the cannonball was shoot horizontally

t is the time

y=0 is the final height of the cannonball

y_{o}=1.96 m is the initial height of the cannonball

g=9.8 m/s^{2} is the acceleration due gravity

Isolating t from (2):

t=\sqrt{-\frac{2(y-y_{o})}{g}} (3)

t=\sqrt{-\frac{2(0 m-1.96 m)}{9.8 m/s^{2}}} (4)

t=0.63 s (5)

Substituting (5) in (1):

x=(23 m/s) cos(0\°) 0.63 s (6)

Finally:

x=14.49 m

5 0
3 years ago
Joaquin has hockey practice at the same ice rink where Alton has curling practice. One day, they were both playing on the ice wi
joja [24]

the puck recoils in each case.

larger mass stone gives puck greater recoil, smaller stone, smaller recoil

8 0
3 years ago
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What is the use of an inclined plane​
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Answer:

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Inclined planes are used to lift heavy objects to higher places.

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If the pendulum is brought on the moon where the gravitational acceleration is about g/6, approximately what will its period now
Andru [333]

Answer:

The new period will be √6 *T

Explanation:

period ,T=2π√(L/g)       ................equation 1

where T is the period on earth

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T1 = 2π√[L/(g/6)]

T1=2π√(6L/g)               ...............equation 2

divide equation 2 by 1

T1/T =2π√(6L/g)÷2π√(L/g)

T1/T =√(6L/L)

T1/T =√6

T1 = √6 *T

5 0
4 years ago
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