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Mrrafil [7]
3 years ago
8

describe a way that people might be able to solve each envioronmental problem listed below. coal mining can harm habitats and ca

use pollution.
Chemistry
1 answer:
Lera25 [3.4K]3 years ago
5 0
Use Solar panels
Wind turbines 
Hydroelectrically means of sourses
Bio fuels
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g Calculate the pH when (a) 24.9 mL and (b) 25.1 mL of 0.100 M HNO3 have been added to 25.0 mL of 0.100 M KOH solution.
jarptica [38.1K]

Answer:

Following are the responses to the given choices:

Explanation:

For point a:

Using the acid and base which are strong so,

moles of H^+ (fromHNO_3)

= 24.9\ mL \times 0.100\ M \\\\= \frac{24.9}{1000\ L} \times 0.100\  M \\\\= 2.49 \times 10^{-3} \ mol

moles of OH^{-} (from KOH)

= 25.0\ mL \times 0.100\ M \\\\= \frac{25.0}{1000 \ L} \times 0.100 \ M \\\\\= 2.50 \times  10^{-3}\  mol  

1\ mol H^{+} \ neutralizes\  1\ mol\  of\  OH^{-}

So,  (2.50 \times 10^{-3} mol - 2.49 \times 10^{-3} mol) i.e. 1 \times 10^{-5} mol of OH^- in excess in total volume (24.9+25.0) \ mL = 49.9 \ mL i.e. concentration of OH^- = 2 \times 10^{-4}\ M

p[OH^{-}] = -\log [OH^{-}] = -\log [2 \times 10^{-4}\ mol] = 3.70

Since, pH + pOH = 14,

so,

\to pH = 14- pOH = 14- 3.70 = 10.30  

For point b:

moles of OH^- = from point a = 2.50 \times 10^{-3} \ mol

moles of H^+(fromHNO_3):

= 25.1 mL \times 0.100 M\\\\ = \frac{25.1}{1000}\ L \times 0.100 \ M\\\\ = 2.51\times 10^{-3} \ mol

1 mol H^+ neutralizes 1 mol of OH^-

So, (2.51 \times 10^{-3}\ mol - 2.50 \times 10^{-3}\ mol) i.e. 1 \times 10^{-5} \ mol \ of\  H^+ in excess in the total volume of (25.1+25.0) \ mL = 50.1\ mL i.e. concentration ofH^+ = 2 \times 10^{-4}\  M

Hence, pH = -\log [H^+] = -\log[2 \times 10^{-4}] = 3.70

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When are multiple bonds needed in a lewis structure?
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Use the pictures below to answer these questions: How does Magnesium become an ion? What is the charge of the Magnesium ion?
marusya05 [52]

Answer:

Explanation:

The bottom picture shows a Mg atom. There are two electrons on the outside ring. When Mg reacts with something, these 2 electrons are given away. The top picture records that fact.

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How do you determine the number of electrons an atom will gain or loose
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In general, metals will lose electrons to become a positive cation and nonmetals will gain electrons to become a negative anion. Hydrogen is an exception, as it will usually lose its electron. Metalloids and some metals can be can lose or gain electrons. This is not always true, as elements such as nitrogen can lose electrons to become positive. When an ionic compound forms, the more electronegative element will gain electrons and the less electronegative element will lose electrons. Hope this helps :)



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Which of the following will form a metallic bond with a metal?
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