The value of x is 120°
Explanation:
It is given that ABC is a straight line.
Also, ∠CBE = 20° and ∠CAF = 40°
We need to determine the value of ∠DBE
Let ∠DBE = x
Since, ∠CAF and ∠ABD are alternate interior angles.
By the alternate interior angles theorem, "if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are equal".
Thus, ∠CAF and ∠ABD are equal.
Hence, ∠CAF = ∠ABD = 40°
Since, we know that, the angles in a straight line add up to 180°, we have,
∠ABD + ∠DBE + ∠CBE = 180°
Substituting the values, we get,
40° + x + 20° = 180°
Adding, we have,
60° + x = 180°
Subtracting both sides by 60, we have,
x = 120°
Thus, the value of x is 120°
Answer:
Step-by-step explanation:
All that we have to do is add the 3 and 5 so it's basically like combining like terms. So the first blank is 8.
Now we add the x and the 5x which is 6x, all we're doing is adding the x's.
Now we do add the two negative 10 and 7. So what is -10 + - 7 we add them normally but we'll still have the negative in front of them. So it's -17.
The true statement about the graph of the function f(x) = x3 - 2x2 + 4x – 8 is (B) The function has 1 real zero that occurs 1 time.
<h3>How to determine the true statement</h3>The function of f(x) is represented as:
Differentiate the function f(x)
Calculate the minimum value using:
So, we have:
Substitute 2/3 in f'(x)
The value of f'(2/3) is greater than 0.
This means that the function f(x) has 1 real zero, and it occurs once at point (2,0)
Hence, the true statement is (b)
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