Answer: Extinction
Animals on the verge of extinction are considered endangered species. Some could argue that the phrasing "threatened" is synonymous to "endangered". Some classify extinction based on if the species is completely wiped out in the wild, or if the species is completely gone (both in the wild and in zoos for instance). Extinction events are not solely due to the changes in atmosphere, but also due to lack of food or habitat, among other possible factors.
Commensalism is where one benefits from the relationship and the other is neither harmed nor be if it’s. Therefore the feather lice and the flies would be commensalism
The answer is A. 2 electrons will go in 1s orbital, 2 more electrons will go in 2s orbital. because the last 5 electrons will go in the 2p orbital but you only want the s orbitals
To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.
We want to standardize a H₂SO₄ solution with NaOH. The neutralization reaction is:
H₂SO₄ + 2 NaOH ⇒ Na₂SO₄ + H₂O
The buret, which contains NaOH, reads initially 0.63 mL, and 44.73 mL at the endpoint. The used volume of NaOH is:
44.10 mL of 0.450 M NaOH are used for the titration. The reacting moles of NaOH are:
The molar ratio of H₂SO₄ to NaOH is 1:2. The moles of H₂SO₄ that react with 0.0198 moles of NaOH are:
0.00990 moles of H₂SO₄ are in 20.00 mL of solution. The molarity of H₂SO₄ is:
![[H_2SO_4] = \frac{0.00990mol}{0.02000} = 0.495 M](https://tex.z-dn.net/?f=%5BH_2SO_4%5D%20%3D%20%5Cfrac%7B0.00990mol%7D%7B0.02000%7D%20%3D%200.495%20M)
To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.
Learn more: brainly.com/question/2728613
<span>The enthalpy of the reaction in an aqueous
solution can be determined by taking the difference between the summation of
enthalpies of the products multiplied to their respective stoichiometric
coefficient and the summation of enthalpies of the reactants multiplied to
their respective stoichiometric
coefficient. In this case, the equation is -241(6) + -393.5 (5) -[-119.9] equal to 641.4 kJ </span>
