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kirza4 [7]
2 years ago
14

To standardize an H2SO4 solution, you put 20.00 mL of it in a flask with a few drops of indicator and put 0.450 M NaOH in a bure

t. The buret reads 0.63 mL at the start and 44.73 mL at the end point. Find the molarity of the H2SO4 solution. Start by writing a balanced chemical equation for this neutralization reaction. Question 5 options: 0.250 M
Chemistry
1 answer:
hram777 [196]2 years ago
7 0

To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.

We want to standardize a H₂SO₄ solution with NaOH. The neutralization reaction is:

H₂SO₄ + 2 NaOH ⇒ Na₂SO₄ + H₂O

The buret, which contains NaOH, reads initially 0.63 mL, and 44.73 mL at the endpoint. The used volume of NaOH is:

V = 44.73 mL - 0.63 mL = 44.10 mL

44.10 mL of 0.450 M NaOH are used for the titration. The reacting moles of NaOH are:

0.04410 L \times \frac{0.450mol}{L} = 0.0198 mol

The molar ratio of H₂SO₄ to NaOH is 1:2. The moles of H₂SO₄ that react with 0.0198 moles of NaOH are:

0.0198 mol NaOH \times \frac{1molH_2SO_4}{2molNaOH} = 0.00990 molH_2SO_4

0.00990 moles of H₂SO₄ are in 20.00 mL of solution. The molarity of H₂SO₄ is:

[H_2SO_4] = \frac{0.00990mol}{0.02000} = 0.495 M

To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.

Learn more: brainly.com/question/2728613

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The mineral galena is composed of lead(II) sulfide and has an average density of 7.46 g/cm³.
postnew [5]

The mineral galena is composed of lead(II) sulfide and has an average density of 7.46 g/cm³. Moles of lead(II) sulfide in 1.00 ft³ of galena are 883 mol PbS.

<h3>What is moles of compound?</h3>

A very large number of molecules, atoms, or other particles are referred to as a "mole," which is a unit of measurement in chemistry. The number of moles in one unit is 6.02214 x 1023, and it is known as Avogadro's Number. These figures are crucial in providing information on the quantity of the constituent elements. A mole of a substance might be as little as a few grams or as much as hundreds of grams.

One mole (or formula unit) of a chemical is equal to 6.022 x 10²³ molecules (ionic). A chemical's molar mass represents the mass of 1 mole of that substance. To put it another way, it tells you how many grams there are in a chemical per mole.

To learn more about moles visit:

brainly.com/question/26416088

#SPJ4

7 0
1 year ago
How many grams of water can be produced from 10 moles of hydrogen gas?
Veseljchak [2.6K]
10 moles of H2 reacts with 5 moles of O2 creating 10 moles of water.
Water has the molar mass 18 g/mole
10 · 18g = 180 g 
180 g of water can be produced from 10 moles of hydrogen gas.
8 0
3 years ago
Need help calculating atomic mass (see pohoto for more info)
polet [3.4K]

Answer:

28.1

Explanation:

Divide the percentage abundances by 100:

92.2% ÷ 100 = 0.922

4.7% ÷ 100 = 0.047

3.1% ÷ 100 = 0.031

multiply them by their corresponding mass number:

0.922×28 = 25.816

0.047×29 = 1.363

0.031×30 = 0.93

add them all together to get your final answer:

25.816 + 1.363 + 0.93 = 28.109

to one decimal place:

28.1

I hope that helps!!!

5 0
2 years ago
Read 2 more answers
State, in terms of electrons, why the radius of Na+ ion in the table salt is smaller than the radius of a Na atom.
Anastaziya [24]

Answer:

• The Na atom is formed when the Na+ ion gains an electron.

• A Na+ ion has 10 electrons and a Na atom has 11 electrons.

• A sodium atom has one more electron shell than a sodium ion.

• A Na+ ion is formed when a Na atom loses an electron

3 0
2 years ago
A gas occupies a volume of 0.2 L at 176 mm Hg. What volume will the gas occupy at 760 mm Hg?
nignag [31]

Answer:

V_2=0.046L

Explanation:

Hello,

In this case, we apply the Boyle's law as an inversely proportional relationship allowing us to understand the pressure-volume behavior as shown below:

P_1V_1=P_2V_2

In such a way, solving for the final volume V2, we obtain:

V_2=\frac{P_1V_1}{P_2}=\frac{0.2L*176mmHg}{760mmHg}  \\\\V_2=0.046L

Best regards.

8 0
2 years ago
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