The coefficient of static friction between the chair and the floor is 0.67
Explanation:
Given:
Weight of the chair = 25kg
Force = 165 N (F_applied)
Force = 127 N (F_max)
To find: Coefficient of static friction
The “coefficient of static friction” between a chair and the floor is defined as the ration of maximum force to the normal force acting on the chair
μ_s=
The F_n is equal to the weight multiplied by its gravity
∴
=mg
Thus the coefficient of static friction changes as
μ_s=![F_{max}/mg](https://tex.z-dn.net/?f=F_%7Bmax%7D%2Fmg)
μ_{s} = ![=165N/((25kg)\times(9.80 m/s^2 ) )](https://tex.z-dn.net/?f=%3D165N%2F%28%2825kg%29%5Ctimes%289.80%20m%2Fs%5E2%20%29%20%29)
= 0.67
"The position of each element in the table gives important information about its structure, properties, and behavior in chemical reactions. Specifically, an element's position in the periodic table helps you figure out its electron configuration, how the electrons are organized around the nucleus."
F = 52000 N
m = 1060 kg
a= F/m = 52000 N/1060 kg = 49.0566 m/s^2