- The bullet can travel about distance of (2115 m)
- Velocity can be regarded as the ratio of distance to time
- Velocity= (distance / time)
Given: velocity= 450 m/s
Time= 4.7s
- Distance= ( velocity × time)
<em>If we substitute the values</em>
= 2115 m
Therefore, the bullet can travel about 2115 m
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Answer:
20 m/s
Explanation:
The frictional force the road exerts on the car provides the centripetal force that keeps the car in circular motion along the curve:
where
F is the centripetal force
m is the mass of the car
r is the radius of the curve
v is the speed of the car
In this problem we have:
m = 2000 kg
r = 200 m
F = 4000 N is the maximum force
Re-arranging the equation, we can calculate the maximum speed v corresponding to this force:
Answer:
(a)
(b)
Explanation:
<u>For Earth we have:</u>
- mass of earth,
- radius of earth,
- orbital radius,
- period of rotation,
- period of revolution,
(a)
Angular momentum,
∵...............................(1)
For a particle of mass m moving in a circular path at a distance r from the axis,
&
Putting respecstive values in eq. (1)
To model earth as a particle is reasonable because the distance between the sun and the earth is very large s compared to the radius if the earth.
(b)
For a uniform sphere of mass M and radius R and an axis through its center,
using eq. (1)
Answer:
a)188.65m
b)154.35m
c)243.7m
Explanation:
Given data:
(a) The distance from the kicker to each of the 2 spectators is given by:
where,
v= speed of sound
=time taken for the sound waves to reach the ears
m
(b)
where,
v= speed of sound
=time taken for the sound waves to reach the ears
(c)As the angle b/w slight lines from the two spectators to the player is right angle,
hypotenuse=the distance b/w 2 spectators
and, the slight lines are the other 2 lines
Answer:
D. Fingerprints
Explanation:
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