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Elodia [21]
2 years ago
5

The air at the top of Mount Everest has pressures of 201.0 torr N2, 50.0 torr O2, 2.0 torr Ar, and 0.5 torr CO2. What is the tot

al air pressure at the top of the highest peak in the world? Show all work to receive full credit.
Chemistry
1 answer:
nordsb [41]2 years ago
3 0

Answer:

The total air pressure at the top of the highest peak in the world is 253.5 torr

Explanation:

The partial pressures of the gases present at the top of Mount Everest are;

Nitrogen, N₂ = 201.0 torr

Oxygen, O₂ = 50.0 torr

Argon, Ar = 2.0 torr

Carbon dioxide, CO₂ = 0.5 torr

By Dalton's law of partial pressure, the total pressure that a mixture of gases exerts is equal to the sum of the partial pressures of the individual gases

Mathematically, the law can be expressed as follows;

Total pressure, P = ∑P_i = P₁ + P₂ + · · ·

From which we have;

The total air pressure at the top of the highest peak in the world, Mount Everest, P_{Total Mont Everest} = The sum of the partial pressures of N₂, O₂, Ar, and CO₂

P_{Total Mont Everest} = 201.0 torr + 50.0 torr + 2.0 torr + 0.5 torr = 253.5 torr

P_{Total Mont Everest} = 253.5 torr = 0.33355263 atmosphere

Therefore, the total air pressure at the top of the highest peak in the world,  P_{Total Mont Everest} = 253.5 torr

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Answer:

Pretty sure its a mineral

Explanation:

Beeswax is a naturally occurring wax secreted mainly by honeybees A. mellifera, for constructing honey combs (Tulloch, 1970a). Unhydrolyzed beeswax consists of approximately 71% esters, 15% hydrocarbons, 8% free fatty acids, and 6% other components (Tulloch, 1970b).

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3 years ago
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A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s
Alla [95]

<u>Answer:</u> The percent yield of the 1-bromobutane is 48.65 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For NaBr:</u>

Given mass of NaBr = 11.1 g

Molar mass of NaBr = 103 g/mol

Putting values in equation 1, we get:

\text{Moles of NaBr}=\frac{11.1g}{103g/mol}=0.108mol

The chemical equation for the reaction of 1-butanol and NaBr is:

\text{1-butanol + NaBr}\rightarrow \text{1-bromobutane}

By Stoichiometry of the reaction

1 mole of NaBr produces 1 mole of 1-bromobutane

So, 0.108 moles of NaBr will produce = \frac{1}{1}\times 0.108=0.108 moles of 1-bromobutane

  • Now, calculating the mass of 1-bromobutane from equation 1, we get:

Molar mass of 1-bromobutane = 137 g/mol

Moles of 1-bromobutane = 0.108 moles

Putting values in equation 1, we get:

0.108mol=\frac{\text{Mass of 1-bromobutane}}{137g/mol}\\\\\text{Mass of 1-bromobutane}=(0.108mol\times 137g/mol)=14.80g

  • To calculate the percentage yield of 1-bromobutane, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of 1-bromobutane = 7.2 g

Theoretical yield of 1-bromobutane = 14.80 g

Putting values in above equation, we get:

\%\text{ yield of 1-bromobutane}=\frac{7.2g}{14.80g}\times 100\\\\\% \text{yield of 1-bromobutane}=48.65\%

Hence, the percent yield of the 1-bromobutane is 48.65 %

5 0
3 years ago
A 25 gram(m) metal ball is heated to 200C(delta T) with 2330 Joules(q) of energy. What is the specific heat of the metal?
Dominik [7]

Answer:

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Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q= 2330 J
  • c= ?
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Replacing:

2330 J= c*25 g* 200 °C

Solving:

c=\frac{2330 J}{25 g* 200 C}

c=0.466 \frac{J}{g*C}

<u><em>The specific heat of the metal is 0.466 </em></u>\frac{J}{g*C}<u><em></em></u>

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