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Flura [38]
4 years ago
9

Alexandra knows that the atomic number of the element potassium, K, is 19. She also knows that one particular isotope of potassi

um has a mass number of 39. How many neutrons can be found in the nucleus of this isotope of potassium?
A) 19

B) 20

C) 39

D) 58
Physics
1 answer:
fiasKO [112]4 years ago
8 0
I believe the answer is 58 but I’m not sure
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Which kind of energy transformation occurs during skydiving? A) mechanical to gravitational B) gravitational to kinetic C) kinet
Aleks [24]

B) gravitational to kinetic

Explanation:

The skydiver, when he is located at a certain height h above the ground, possesses gravitational potential energy, equal to:

U=mgh

where m is the mass of the skydiver, g is the gravitational acceleration and h is the height above the ground. As he falls, its height h decreases, while his speed v increases, so part of the gravitational potential energy is converted into kinetic energy, which is given by

K=\frac{1}{2}mv^2

so, we see that as v increases, the kinetic energy increases. Therefore the correct answer is

B) gravitational to kinetic

7 0
3 years ago
Read 2 more answers
If a car stopped then accelerates at 25m/s2 for 2 seconds what is the final velocity of the car?
nalin [4]
The velcocity equals acceleration times time
which is 50 ms per sec
5 0
4 years ago
Technician A says that if starter drive clearance is too small, the starter will produce a noise during cranking. Technician B s
Ronch [10]

Answer:

Both Technicians A and B are wrong in there answers.

Explanation:

Starter Drives are rotating mechanical component use to drive another component (flywheel) to start an engine. And thus they are known as starters. Starters are smaller than the component they drive. They are found commonly in automobiles.

The starter and the driven component(gear) are supposed to fit closely, with some clearance between the two gears so as to operate without noise. When the<u> clearance is too small </u>there will be a <u>noise after cranking,</u>  and   when the <u>clearance is too great</u> there be <u>noise before cranking</u>.

Cranking simply means starting an engine or the initial rotating of an engine to start it.  

8 0
3 years ago
Use the information presented in the graph to answer
Angelina_Jolie [31]

1) Segments A and C

2) Segment C

3) 40 m/s

4) 0

Explanation:

The graph is missing: find it in attachment.

1)

Here we want to find which segments show acceleration.

Acceleration is defined as the rate of change of velocity of an object; mathematically:

a=\frac{\Delta v}{\Delta t}

where

\Delta v is the change in velocity

\Delta t is the time interval

On a velocity-time graph, an object has acceleration if its velocity, v, changes versus time.

In this problem, we see that this situation occurs in two segments:

- In segment A, where the is a change in velocity (\Delta v>0), so there is an acceleration

- In segment C, where the is also a change in velocity (\Delta v>0), so there is an acceleration

B)

Here we want to find in which segment the object is slowing down.

For an object to slow down, the final velocity must be less than the initial velocity, which means that the change in velocity must be negative:

\Delta v = v-u

where

v is the final velocity

u is the initial velocity

For the graph in the problem, we see that:

- For segment A, the final velocity is greater than the initial velocity, so the object is speeding up

- For segment B, the final velocity is equal to the initial velocity, so the object is neither speeding up nor slowing down

- For segment C, the final velocity is less than the initial velocity, so the object is slowing down

So, the segment in which the object is slowing down is segment C.

C)

The velocity of an object is defined as the displacement covered per unit time:

v=\frac{d}{\Delta t}

where

d is the displacement

\Delta t is the time elapsed

On a velocity-time graph, the velocity is represented on the y-axis, while the time is represented on the x-axis.

Therefore, it is possible to read directly the value of the velocity from the y-axis.

For segment B, we see that the velocity is constant, and its value is

v_B=40 m/s

D)

As we stated before, the acceleration of an object is the rate of change of its velocity:

a=\frac{\Delta v}{\Delta t}

where

\Delta v is the change in velocity

\Delta t is the time interval

Here we want to find the acceleration for segment B. For this segment, we observe that:

- The velocity does not change, so \Delta v = 0

- The time interval is \Delta t = 9 s - 4 s = 5 s

Therefore, the acceleration in segment B is:

a_B=\frac{0}{5s}=0

6 0
3 years ago
Would a 500 μF or 100 μF capacitor keep a light bulb on longer? Explain your reasoning
balandron [24]

Answer:

The 500 would be able to keep a light bulb on longer.

Explanation:

The 500 would be able to hold more charge than the 100 which means it can keep the light bulb lit for longer.

5 0
3 years ago
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