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cricket20 [7]
3 years ago
6

1. What is work done in holding a 15kg suitcase while waiting for a bus for 15 minutes?

Physics
1 answer:
Tems11 [23]3 years ago
6 0
Work is (force applied) x (distance through which the force moves).

Since the suitcase doesn't move up or down during the 15 minutes,
no work is done ... zero, zip, nada ... according to the real Physics
definition of 'work'.
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A paper filled capacitor is charged to a potential difference of 2.1 V and then disconnected from the charging circuit. The diel
Goryan [66]

Answer:

Part a)

V' = 7.77 Volts

Part b)

k' = 6.27

Explanation:

As we know that capacitor plate is connected across 2.1 V and after charging it is disconnected from the battery

So here we can say that charge on the plates will remain conserved

So we will have

Q = kC(2.1)

now dielectric is removed between the plates of capacitor

so new potential difference between the plates

V' = \frac{Q}{C'}

V' = \frac{kC(2.1)}{C}

V' = 3.7 \times 2.1

V' = 7.77 Volts

Part b)

Now the capacitor plates are again isolated and unknown dielectric is inserted between the plates

So again charge is same so potential difference is given as

V" = \frac{Q}{k'C}

0.59 V = \frac{kCV}{k'C}

0.59 = \frac{3.7}{k'}

k' = 6.27

5 0
3 years ago
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Juliette [100K]

Answer:

Light slows down

Explanation:

8 0
3 years ago
HELP!! ALL MY POINTS WILL BE GIVEN
Marta_Voda [28]

Answer:

-6 m/s^2

Explanation:

30 - 90 = -60

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2 years ago
Read 2 more answers
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Vera_Pavlovna [14]
Copper, gold and silver are three of them.
7 0
3 years ago
PE=30J, m=?, g=10m/s2, h=10m
OleMash [197]
Based on the given, this is probably a gravitational potential energy problem (PEgrav). The formula for PEgrav is:

PEgrav = mgh

Where:
m = mass (kg)
g = acceleration due to gravity
h = height (m)

With this formula you can derive the formula for your unknown, which is mass. First put in what you know and then solve for what you do not know.

PEgrav=mgh
30J=m(10)(10[tex] \frac{30}{100} =m)[/tex]

Do operations that you can with what is given first.

30J=m(100m)

Transpose the 100 to the other side of the equation. Do not forget that when you transpose, you do the opposite operation.

\frac{30}{100} =m

m = 0.30kg

5 0
3 years ago
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