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nalin [4]
3 years ago
13

In 1-2 sentences explain how you would determine the constant k for a spring.

Physics
1 answer:
Dmitrij [34]3 years ago
3 0

To perform an experiment to determine the force constant of a spring, you will need a stand with a boss and clamp, a spiral spring, a meter rule and different weights.

The setup is arranged as shown in the image attached. The natural length of the spring is first recorded. Different weights are added to the spring one after the other and the extension is recorded.

The weight is now plotted on the vertical axis and the extension is plotted on the horizontal axis. The slope of the graph is the force constant of the spring.

Learn more: brainly.com/question/10991960

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The lengths of the mercury column of a mercury thermometer are 1.26cm and 20.86cm respectively at the standard fixed points. Wha
Svetradugi [14.3K]

The temperature of the body is equal to 39.48°C

Why?

To find the temperature of the body that produces 9.0cm of this mercury column, we need to use the formula for linear interpolation. Also, the temperatures to use are based on the Celsius degrees scale.

For the fixed tempetatures, we have:

1.26cm=0\°C(ColdWaterPoint)\\20.86cm=100\°C(BoilingWater)Point\\

We need to use the following formula for linear interpolation:

y=\frac{x-x_{1}}{x_{2}-x_{1}}*(y_{2}-y_{1})+y_{1}

Then, we have:

1.26cm=0\°C\\20.86cm=100\°C\\9.0cm=???\\\\x_{1}=1.26cm,y_{1}=0\°C\\\\x_{2}=20.86cm,y_{2}=100\°C\\\\x=9.0cm,y=???

So, interpolating we have:

y=\frac{(9cm-1.26cm)}{(20.86cm-1.26cm)}*(100\°C -0\°C)+0\°C\\\\y=0.39*100\°C=39.48100\°C

Hence, the temperature of the body is equal to 39.48°C

Have a nice day!

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When a source of dim orange light shines on a photosensitive metal, no photoelectrons are ejected from its surface. what could b
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To expel electrons from a piece of metal, the incoming light must have a minimum frequency to cause a photoelectric effect, i.e., the ejection of photoelectrons from a metal surface, which is also known as the metal's threshold frequency.

If v = frequency of incident photon and vth= threshold frequency, then,

  • For v < vth, there will be no ejection of photoelectron.
  • For v = vth, photoelectrons are just ejected from the metal surface, in this case, the kinetic energy of the electron ejected is zero
  • For v > vth, then photoelectrons will come out of the surface along with kinetic energy

Therefore, we would have to increase the frequency of incident light so that it becomes greater than the threshold frequency of that surface, and consequently a photoelectric process takes place.

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