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Natali [406]
3 years ago
5

Round the following numbers to the number of significant figures indicated:

Chemistry
1 answer:
Kruka [31]3 years ago
7 0
  1. 3.5
  2. 9
  3. 24.7
  4. 8.01
  5. 0.006
  6. 13(1.25×1012=12.65)

Explanation:

Above we have simply looked the condition that where we put decimal point that gives your needed answer after round off.

For example:

we have to make 2 s.f from 345 so we kept decimal after 3 and we rounded off to make 3.5 from 3.45

Hope you got it

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7. The equilibrium constant Kc for the reaction H2(g) + I2(g) ⇌ 2 HI(g) is 54.3 at 430°C. At the start of the reaction there are
Juli2301 [7.4K]

Answer:

[H2] = 0.0692 M

[I2] = 0.182 M

[HI] =  0.826 M

Explanation:

Step 1: Data given

Kc = 54.3 at 430 °C

Number of moles hydrogen = 0.714 moles

Number of moles iodine = 0.984 moles

Number of moles HI = 0.886 moles

Volume = 2.40 L

Step 2: The balanced equation

H2 + I2 → 2HI

Step 3: Calculate Q

If we know Q, we know in what direction the reaction will go

Q = [HI]² / [I2][H2]

Q= [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Q =(n(HI)²) /(nH2 *nI2)

Q = 0.886²/(0.714*0.984)

Q =1.117

Q<Kc This means the reaction goes to the right (side of products)

Step 2: Calculate moles at equilibrium

For 1 mol H2 we need 1 mol I2 to produce 2 moles of HI

Moles H2 = 0.714 - X

Moles I2 = 0.984 -X

Moles HI = 0.886 + 2X

Step 3: Define Kc

Kc = [HI]² / [I2][H2]

Kc = [n(HI) / V]² /[n(H2)/V][n(I2)/V]

Kc =(n(HI)²) /(nH2 *nI2)

KC = 54.3 = (0.886+2X)² /((0.714 - X)*(0.984 -X))

X = 0.548

Step 4: Calculate concentrations at the equilibrium

[H2] = (0.714-0.548) / 2.40 = 0.0692 M

[I2] = (0.984 - 0.548) / 2.40 = 0.182 M

[HI] = (0.886+2*0.548) /2.40 = 0.826 M

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What process do plants undergo to produce chemical energy?
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What is my control group in my experiment and why is it that?
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Your control group would be the batteries since you CONTROL what brand you're using, for which one lasts the longest...aren't you suppose to figure that out when you do the experiment?
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what pressure in N/m2 would be exerted if a 65 kg person were sitting on a stool with a seat diameter of 12 inches?
yaroslaw [1]

d = diameter of the seat = 12 inch

we know that , 1 inch = 0.0254 m

hence

d = diameter of the seat = 12 inch = 12 (0.0254) m = 0.305 m

r = radius of seat = diameter/2 = d/2 = 0.305/2 = 0.1525 m

A = area of seat = πr²

m = mass of the person = 65 kg

g = acceleration due to gravity = 9.8 m/s²

F = force due to weight of person on the seat = mg

pressure on the seat is given as

P = F/A

P = mg/A

P = mg/(πr² )

inserting the values

P = (65 x 9.8)/((3.14) (0.1525)²)

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