The empirical formula of c12h24o12 is a carbohydrate.
<h3>Carbohydrate</h3>
A carbohydrate is a biomolecule made up of carbon (C), hydrogen (H), and oxygen (O) atoms, often with a hydrogen-oxygen atom ratio of 2:1 (as in water), and so having the empirical formula Cm(H2O)n (where m may or may not be different from n). All molecules that meet this exact stoichiometric criterion are not, however, automatically categorized as being carbohydrates.
The term is most frequently used in biochemistry, where it is used as a synonym for saccharide, a class of compounds that includes sugars, starches, and cellulose. The four chemical categories of saccharides are monosaccharides, disaccharides, oligosaccharides, and polysaccharides. The smallest carbohydrates, monosaccharides and disaccharides, are sometimes referred to as sugars.
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Answer:
The final molarity of acetate anion in the solution is 0.0046 moles
Explanation:
The balanced equation is
Cu(C₂H₃O₂)₂ + Na₂CrO₄ = CuCrO₄ + 2Na(C₂H₃O₂)
Therefore one mole of Cu(C₂H₃O₂)₂ react with one mole of Na₂CrO₄ to form one mole of CuCrO₄ and two moles of Na(C₂H₃O₂)
Mass of copper (II) acetate present = 0.708 g
Volume of aqueous sodium present = 50 mL
Molarity of sodium chromate = 46.0 mM
Therefore
Number of moles of sodium chromate present = (50 mL/1000)×46/1000 = 0.0023 M
Number of moles of copper (II) acetate present = 181.63 g/mol
number of moles of copper (II) acetate present = (0.708 g/181.63 g/mol) =0.0039 moles
Therefore 0.0039 moles of Cu(C₂H₃O₂)₂ × (2 moles of Na(C₂H₃O₂))/1 Cu(C₂H₃O₂)₂) = 0.00779 moles of Na(C₂H₃O₂)
also 0.0023 moles of Na₂CrO₄ × (2 moles of Na(C₂H₃O₂))/1 Na₂CrO₄) = 0.0046 moles of Na(C₂H₃O₂)
Therefore the Na₂CrO₄ is the limiting reactant and 0.0046 moles of Na(C₂H₃O₂) or acetate anion is formed
Answer:
a. NO2
b. NH3
c. CO2
Explanation:
a. For the pair of compounds CO2 or NO2 the one with the highest boiling point is __________ .
The answer is NO2. It has a higher boiling point than CO2 because it exhibits dipole-dipole interactions.
b. For the pair of compounds NH3 or CH4 the one with the highest boiling point is _________
NH3 has a higher boiling point compared to CH4. This is due to the presence of the hydrogen bonds in NH3,
c. For the pair of compounds CS2 or CO2 the one with the highest boiling point is _________
CS2 has a higher boiling point than CO2. This is because of the high molecular mass of CS2.
Answer:
The volume for a piece of gold that has the mass of 318,67 g is 16,50cm3
Explanation:
Density = mass / volume
Volume = mass/ density
Volume = 318,97 g / 19,32 g/cm3 = 16,50cm3
It will produce high concentration of hydrogen ions if acid ionises completely in water.
