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ryzh [129]
3 years ago
10

Describe a plant/ animal in which you can observe wave motion. State the type of wave and describe in relation to body movement

Physics
2 answers:
Korolek [52]3 years ago
6 0
Trees. Every time the wind blows there is a wave of motion which is movement

mixas84 [53]3 years ago
4 0

Answer:

The wavelike motion usually can be described by the equation:

X(y,t) = Acos(kx - wt) + Bsin(kx - wt), so wavelike motion is usually a periodic motion.

Where k is the wavenumber and w is the frequency.

You can see a wavelike motion in trees when the wind moves them and the branches start to move in oscillatory motion.

Another example of wave motion can be some fishes, that use wavelike motion to impulse in the water.

Another example can be the Vipera ammodytes that move in a wavelike motion, with the objective of increasing its speed and agility in the sand.

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At 1:00 a.m., someone breaks a window in the back of a store and robs the safe. On the way out, the thief is cut on a piece of b
Karolina [17]

Answer:dd

Explanation:

5 0
3 years ago
What amount of force is needed to propel and object of 27 kg to an acceleration of 11,550 m/s^2? (1 point)
aliya0001 [1]

Answer:

311,850 N

Explanation:

We can solve the problem by using Newton's second law:

F=ma

where

F is the net force applied on an object

m is the mass of the object

a is its acceleration

For the object in this problem,

m = 27 kg

a=11550 m/s^2

Substituting, we find the force required:

F=(27)(11550)=311,850 N

3 0
3 years ago
What is another word that can be used to describe the position of the<br> object?
steposvetlana [31]

where the object is located

6 0
3 years ago
Physics Question 100 Points No Spam.
VARVARA [1.3K]

Answer:

- Wind resistance made decrease in speed

-Gravity/Mass made decrease in velocity

Explanation:

7 0
2 years ago
Read 2 more answers
Tourists covered 255 km for a 4-hour ride by car and a 7-hour ride by train. what is the speed of the train, if it is 5 km/h gre
LekaFEV [45]
The distance covered by car is equal to (assuming it is moving by uniform motion) the product between the car's speed and the time of the car ride, 4 h:
S_c = v_c t_c
where
v_c is the car's speed
t_c = 4 h is the duration of the car ride

Similarly, the distance covered by train is equal to the product between the train's speed and the duration of the train ride, 7 h:
S_t = v_t t_t

The total distance covered is S=255 km, which is the sum of the distances covered by car and train:
S=255 km = S_c + S_t
which becomes
255 = 4 v_c + 7 v_t (1)
we also know that the train speed is 5 km/h greater than the car's speed:
v_t = 5 + v_c (2)

If we put (2) into (1), we find
255 = 4v_c + 7(5+v_c)
and if we solve it, we find
v_c = 20 km/h
v_t = 25 km/h

So, the car speed is 20 km/h and the train speed is 25 km/h.

4 0
4 years ago
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