1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arturiano [62]
3 years ago
8

The eyes of amphibians such as frogs have a much flatter cornea but a more strongly curved (almost spherical) lens than do the e

yes of air-dwelling mammals. In mammalian eyes, the shape (and therefore the focal length) of the lens changes to enable the eye to focus at different distances. In amphibian eyes, the shape of the lens doesn't change. Amphibians focus on objects at different distances by using specialized muscles to move the lens closer to or farther from the retina, like the focusing mechanism of a camera. In air, most frogs are nearsighted; correcting the distance vision of a typical frog in air would require contact lenses with a power of about −6.0D .A frog can see an insect clearly at a distance of 10cm . At that point the effective distance from the lens to the retina is 8mm .If the insect moves 5cm farther from the frog, by how much and in which direction does the lens of the frog's eye have to move to keep the insect in focus?0.02cm, toward the retina.0.02cm, away from the retina.0.06cm, toward the retina.0.06cm, away from the retina.
Physics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

0.2cm towards the retina.

Explanation:

the focal length of the frog eye is

(1/f) = (1/10) + (1/0.8)

f = 0.74cm

Since the distance of the object is 15cm Hence

(1/0.74) = (1/15) + (1/V)

V = 0.78cm

Therefore the distance the retina is to move is

0.78cm - 0.8cm = 0.02cm towards the retina.

You might be interested in
Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x.
Contact [7]
The center of mass is given with this formula:
x_c=\frac{\sum_{n=1}^{n=i}m_ix_i}{M}
Velocity is:
v=\frac{dv}{dt}
So, for the velocity of the center of mass we have:
\frac{dx_c}{dt}=\frac{\sum_{n=1}^{n=i}d(m_ix_i)}{Mdt}\\
v_c=\frac{\sum_{n=1}^{n=i}p_i}{M}\\
In our case it is:
v_{xc}=\frac{m_1v_{x1}+m_2v_{x2}}{m_1+m_2}
 
5 0
3 years ago
The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag
CaHeK987 [17]

The speed of tsunami is a.0.32 km. 

Steps involved  :

The equation s = 356d models the maximum speed that a tsunami can move at. It reads as follows: s = 200 km/h d =?

Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32

As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.

To learn more about tsunami refer : brainly.com/question/11687903

#SPJ4

6 0
2 years ago
________ In many cartoon shows, a character runs off a cliff, realizes his predicament, and lets out a scream. He continues to s
IrinaVladis [17]

Answer:

Here the source is moving away from the observer so frequency will be smaller than the actual frequency and since the speed is increasing so the frequency is decreasing with time so correct answer is

D) lower than the original pitch and decreasing as he falls.

Explanation:

As we know by the Doppler's effect of sound we have

so we will have

f = f_o(\frac{v}{v + v_s})

so here when source moves away from the observer with a some speed then the frequency of the sound observed by the observer is smaller than the actual frequency

Here we know that the speed of the source is increasing with time as the source is falling under gravity

So we can say that the pitch of the sound will decrease with time

4 0
3 years ago
Give 2 reasons for fitting heavy commercial vehicles with many tyres​
forsale [732]
Better weight distribution and more stability
4 0
2 years ago
A water wave has a speed of 23.0 meters/second. If the wave’s frequency is 0.0680 hertz, what is the wavelength?
tankabanditka [31]
     Using the Fundamental Equation of Wave, we have:

v=\lambda f \\ \lambda= \frac{23}{0.068}  \\ \boxed {\lambda \approx 338m}

Letter B
3 0
3 years ago
Read 2 more answers
Other questions:
  • The speed of light is about 300,000 km/s (3×105km/s). If Jupiter is 0.72 light hours from the Sun, how far is this?
    7·2 answers
  • A speedboat initially at rest accelerates uniformly at 4.0 m/s (squared) for 7.0 s. How fast is the boat moving after 7.0 s?
    14·1 answer
  • An instrument for observing very small objects is
    13·1 answer
  • A capacitor stores 5.6 x 10-7 C of charge when connected to a 6.0-V battery. How much charge does the capacitor store when conne
    15·1 answer
  • If the Sun and volcanoes were controlling the climate, the climate would
    9·1 answer
  • Exactly one turn of a flexible rope with mass m is wrapped around a uniform cylinder with mass M and radius R.
    8·1 answer
  • 1. What type of interference is happening when intersecting light waves subtract from each other to create dark spots? Which let
    12·1 answer
  • A 50N girl pushes a 10,000 N car with force of 200N. What is the force the car pushes back at the girl? *
    15·1 answer
  • Which is the graph of the polar equation r = 4 cos3 theta
    5·2 answers
  • Please answer the following two questions.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!