Qs 1: m = 1/2*KE*V^2
qs 2: 6,223.39 kg
Answer:
2.72m/s²
Explanation:
Given parameters;
Mass of box = 27.8kg
Force on box = 75.7N
Unknown:
Acceleration = ?
Solution:
Force is the product of mass and acceleration;
Force = mass x acceleration
Now insert the parameters and solve;
75.7 = 27.8 x a
a =
= 2.72m/s²
Answer:

Explanation:
Given that the temperature of
of water and
of water are
at
and
respectively.
Let
, 
and
,
.
The specific heat capacity of water is,
.
Let the final temperature of the mixture be
.
As there is no energy loss, so, the energy loss by the water at higher temperature, i.e.
, will be equal to the energy gain by the water at lower temperature, i.e.
.

[ both sides divided by
]



Now, putting the given value in the above equation, we have


Hence, the temperature of the mixture will be
.
Answer:
A.No. Assuming no other factors (such as air resistance) the first object will have a velocity of 32 feet/second when the other is dropped. Since they will both have the same acceleration, the first distance between them will increase by 32 feet per second.
Explanation: