Answer:
I have two methods to distinguish between concentrated and dilute nitric acid
Method 1: Using magnesium/manganese.
Mg + 2HNO₃ (1%) → Mg(NO₃) + H₂
very very dilute
Mg + 4HNO₃ → Mg(NO₃)+ 2H₂O +2NO₂
concentrated
In the first reaction of magnesium with concentrated nitric acid, hydrogen is evolved.
In the second reaction of magnesium with very very dilute nitric acid, water is evolved.
Using the respective tests for hydrogen and water, we can test them.
Method 2: Using iron.
3 Fe + 8HNO₃→ 3Fe(NO₃)₂ + 4H₂O + 2NO
dilute
Fe + 6HNO₃→ Fe(NO₃)₃ + 3H₂O + 3NO₂
concentrated
In the first case of method 2,
Fe(NO₃)₂ ⇆ Fe²⁺ + (NO₃) ⁻ Iron with valency 2+ is formed
In the second case of method 2,
Fe(NO₃)₃ ⇄ Fe³⁺ + (NO₃) ⁻ Iron with valency 3+ is formed
Brainlist pls!
Answer:
maybe it is true
Explanation:
it can 5×then the normal one
Answer: Strawberries liquefied in a blender
Explanation:
Answer:
0.453 moles
Explanation:
The balanced equation for the reaction is:
2Fe(s) + 3O2(g) ==> 2Fe2O3
From the equation, mass of O2 involved = 16 x 2 x 3 = 96g
mass of Fe2O3 involved = [(2x26) + 3 x 16] x 2
= 100g
Therefore 96g of O2 produced 100g of Fe2O3
32.2g of O2 Will produce 100x32.2/96
= 33.54g of Fe2O3
Converting it to mole using number of mole = mass/molar mass
but molar mass of Fe2O3 = 26 + (16 X 3)
= 74g/mole
Therefore number of mole of 33.54g of Fe2O3 = 33.54/74
= 0.453 moles
Answer:
1632 Hz
Explanation:
We'll begin by calculating the frequency of each wave. This can be obtained as follow:
1st wave:
Velocity (v) = 340 m/s.
Wavelength 1 (λ₁) = 5 m
Frequency 1 (f₁) =?
v = λ₁f₁
340 = 5 × f₁
Divide both side by 5
f₁ = 340 / 5
f₁ = 68 Hz
2nd wave:
Velocity (v) = 340 m/s.
Wavelength 2 (λ₂) = 0.2 m
Frequency 2 (f₂) =?
v = λ₂f₂
340 = 0.2 × f₂
Divide both side by 0.2
f₂ = 340 / 0.2
f₂ = 1700 Hz
Finally, we shall determine the difference in the frequency of both waves.
This can be obtained as follow:
Frequency 1 (f₁) = 68 Hz
Frequency 2 (f₂) = 1700 Hz
Difference =?
Difference = f₂ – f₁
Difference = 1700 – 68
Difference = 1632 Hz