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3 years ago

6

Se lanza una bala con una velocidad inicial de 200 m/s y con un ángulo de inclinación de 30º respecto a la horizontal. Si se con

sidera g=10 m/s2. ¿Cuál es el alcance de la bala?

1 answer:

puteri [66]3 years ago

8 0

Answer:

El alcance de la bala es 3464,1 m.

Explanation:

El alcance de la bala se puede calcular como sigue:

$y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}}$

En donde:

y: es la altura final = 0

$y_{0}$ : es la altura inicial = 0

x: es el alcance

θ: es el angulo respecto a la horizontal = 30°

$v_{0}$ : es la velocidad inicial = 200 m/s

g: es la gravedad = 10 m/s²

Entonces, tenemos:

$y = y_{0} + tan(\theta)*x - \frac{g}{2}*\frac{x^{2}}{(v_{0}cos(\theta))^{2}}$

$x = \frac{2tan(\theta)*(v_{0}cos(\theta))^{2}}{g} = \frac{2tan(30)*(200 m/s*cos(30))^{2}}{10 m/s^{2}} = 3464,1 m$

Por lo tanto, el alcance de la bala es 3464,1 m.

Espero que se te sea de utilidad!

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