What is the molality of a solution that contains 5 moles of solute in 100 kilograms of water?
2 answers:
Answer:
Explanation:
Hello,
In this case, molality is defined as:
Whereas the mass of the solvent is given in kilograms. In such a way, for 5 moles of solute and 100 kg of water, the molality turns out:
Now it is important to notice that the molal units (m) equals mol/kg, thereby:
Best regards.
<span>Answer:
molality = (moles of solute) / (kilogram of solvent)
moles of solute = (75.2 g AgClO4) / (mole mass AgClO4)
moles of solute = (75.2 g AgClO4) / (207.3206 g/mol)
moles of solute = 0.3627232 mol
molality = (0.3627232 mol) / (0.0752 Kg)
molality = 4.8234468 m or 4.82 m rounded to three significant figures </span>
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