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taurus [48]
3 years ago
12

What is the molality of a solution that contains 5 moles of solute in 100 kilograms of water?

Chemistry
2 answers:
vladimir2022 [97]3 years ago
5 0

Answer:

m=0.05m

Explanation:

Hello,

In this case, molality is defined as:

m=\frac{n_{solute}}{m_{solvent}}

Whereas the mass of the solvent is given in kilograms. In such a way, for 5 moles of solute and 100 kg of water, the molality turns out:

m=\frac{5mol}{100kg}\\ m=0.05\frac{mol}{kg}

Now it is important to notice that the molal units (m) equals mol/kg, thereby:

m=0.05m

Best regards.

slega [8]3 years ago
3 0
<span>Answer:
molality = (moles of solute) / (kilogram of solvent)

moles of solute = (75.2 g AgClO4) / (mole mass AgClO4)
moles of solute = (75.2 g AgClO4) / (207.3206 g/mol)
moles of solute = 0.3627232 mol

molality = (0.3627232 mol) / (0.0752 Kg)
molality = 4.8234468 m or 4.82 m rounded to three significant figures </span>
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