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3 years ago

How many grams of sulfur must be burned to give 100.0 g of So2

Chemistry

1 answer:

andriy [413]3 years ago

4 0

Answer:

50 g of S are needed

Explanation:

To star this, we begin from the reaction:

S(s) + O₂ (g) → SO₂ (g)

If we burn 1 mol of sulfur with 1 mol of oxygen, we can produce 1 mol of sulfur dioxide. In conclussion, ratio is 1:1.

According to stoichiometry, we can determine the moles of sulfur dioxide produced.

100 g. 1mol / 64.06g = 1.56 moles

This 1.56 moles were orginated by the same amount of S, according to stoichiometry.

Let's convert the moles to mass

1.56 mol . 32.06g / mol = 50 g

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3 years ago

How does particles of substance behave at its melting point?

ivolga24 [154]

When a substance is heated, its atoms gain energy and begin to vibrate rapidly within the lattice of the substance (the substance expands). As more heating continues, the atoms gain even more energy and move more rapidly until they are able to overcome the force of the bonds, that hold the atoms together in the lattice, until the structure is disrupted.

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3 years ago

Read 2 more answers

A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s

Alla [95]

Answer: The percent yield of the 1-bromobutane is 48.65 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For NaBr:

Given mass of NaBr = 11.1 g

Molar mass of NaBr = 103 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaBr}=\frac{11.1g}{103g/mol}=0.108mol$

The chemical equation for the reaction of 1-butanol and NaBr is:

$\text{1-butanol + NaBr}\rightarrow \text{1-bromobutane}$

By Stoichiometry of the reaction

1 mole of NaBr produces 1 mole of 1-bromobutane

So, 0.108 moles of NaBr will produce = $\frac{1}{1}\times 0.108=0.108$ moles of 1-bromobutane

Now, calculating the mass of 1-bromobutane from equation 1, we get:

Molar mass of 1-bromobutane = 137 g/mol

Moles of 1-bromobutane = 0.108 moles

Putting values in equation 1, we get:

$0.108mol=\frac{\text{Mass of 1-bromobutane}}{137g/mol}\\\\\text{Mass of 1-bromobutane}=(0.108mol\times 137g/mol)=14.80g$

To calculate the percentage yield of 1-bromobutane, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of 1-bromobutane = 7.2 g

Theoretical yield of 1-bromobutane = 14.80 g

Putting values in above equation, we get:

$\%\text{ yield of 1-bromobutane}=\frac{7.2g}{14.80g}\times 100\\\\\% \text{yield of 1-bromobutane}=48.65\%$

Hence, the percent yield of the 1-bromobutane is 48.65 %

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3 years ago

What creates a thermocline?

vredina [299]

Answer:

here are the answers to all the questions on the quiz Phytoplankton

There would be no ocean life without _____.

thermocline

marine snow

phytoplankton

runoff

Phytoplankton is the answer.

What creates a thermocline?

a series of strong ocean storms

a difference in water temperature

a difference in the amount of phytoplankton

a change in the phytoplankton population

a difference in water temperature is the answer

What limits the growth of phytoplankton?

It is limited by the amount of water that runs off into the ocean.

It is limited by the number of fish eating the phytoplankton directly.

It is limited by the depth of the water in the ocean.

It is limited by the amount of nutrients in the water.

It is limited by the amount of nutrients in the water is the answer

What are phytoplankton? (Select all that apply.)

They are organisms that support all other life in the oceans.

They are tiny plants that drift with the currents of the ocean.

They are small plants and animals that exist both on land and in the ocean.

They are microscopic animals that drift with the currents of the wind.

They are organisms that support all other life in the oceans.

They are tiny plants that drift with the currents of the ocean.

are the answers

Which is a possible food chain in the ocean from start to finish?

phytoplankton, zooplankton, small fish, large fish, large shark

zooplankton, phytoplankton, large fish, small fish, large shark

phytoplankton, large shark, zooplankton, large fish, small fish

large shark, large fish, small fish, zooplankton, phytoplankton

phytoplankton, zooplankton, small fish, large fish, large shark is the answer

Hope this helps!

did the quiz and got 100%

May I get braineist pls

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2 years ago

I need the answer for this question

ch4aika [34]

I want to say A only... Hope I helped!!

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