They are found in group 3 of the periodic table.
Answer:
C₈H₈O₃
Explanation:
The empirical formula is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the molar ratio of C:H:O.
Assume 100 g of the compound.
1. Calculate the mass of each element.
Then we have 63.15 g C, 5.30 g H, and 31.55 g O.
2. Calculate the moles of each element
![\text{Moles of C} = \text{63.15 g C} \times \dfrac{\text{1 mol C}}{\text{12.01 g C}} = \text{5.258 mol C}\\\\\text{Moles of H} = \text{5.30 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H }} = \text{5.258 mol H}\\\\\text{Moles of O} = \text{31.55 g O} \times \dfrac{\text{1 mol O}}{\text{16.00 g O }} = \text{1.972 mol O}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20C%7D%20%3D%20%5Ctext%7B63.15%20g%20C%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20C%7D%7D%7B%5Ctext%7B12.01%20g%20C%7D%7D%20%3D%20%5Ctext%7B5.258%20mol%20C%7D%5C%5C%5C%5C%5Ctext%7BMoles%20of%20H%7D%20%3D%20%5Ctext%7B5.30%20g%20H%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20H%7D%7D%7B%5Ctext%7B1.008%20g%20H%20%7D%7D%20%3D%20%5Ctext%7B5.258%20mol%20H%7D%5C%5C%5C%5C%5Ctext%7BMoles%20of%20O%7D%20%3D%20%5Ctext%7B31.55%20g%20O%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20O%7D%7D%7B%5Ctext%7B16.00%20g%20O%20%7D%7D%20%3D%20%5Ctext%7B1.972%20mol%20O%7D)
3. Calculate the molar ratio of the elements
Divide each number by the smallest number of moles
C:H:O = 5.258:5.258:1.972 = 2.667:2.666:1
4. Multiply by a number to make each ratio close to an integer
Multiply the ratios by three.
2.667:2.666:1 = 8.000:8.000:3 ≈ 8:8:3
5. Write the empirical formula
EF = C₈H₈O₃
C₃H₃O i think. tell me if i’m wrong
Specific heat capacity= Quantity of heat/massxΔT
Shc of iron (constant)= 0.4494J/³C for 1g
1.49kg=1490g
Q=1490x(22-155)x0.4494
Q=<span>89057.598J</span>
False is the answer
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