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MaRussiya [10]
3 years ago
7

You throw a ball into a box and close the lid. You hear the ball bouncing around inside as the ball’s energy changes from gravit

ational potential energy to kinetic energy, to elastic potential energy, and so on. If you wait a minute or two, what will have happened to the ball’s energy?
Physics
1 answer:
beks73 [17]3 years ago
5 0

Answer:

Thermal energy.

Explanation:

We know that energy is conserved and it only transform one form to another form ,Like potential energy transform in to kinetic energy when a ball fall down from a height and obtain some velocity.

In this case energy changes from gravitational energy to kinetic energy then elastic energy and after some time this energy will convert in to thermal energy.

So the answer is thermal energy.

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Which of Newton's laws says that an object in motion stays in motion, and an object at rest stays at rest unless acted upon by a
Vinil7 [7]
Newtons first law states that.
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How does a decrease in thermal energy affect the kinetic energy of the particles in each state of matter?
Svetlanka [38]

Answer:

kinetic and potential energy). The opposite is true when you remove thermal energy: Particles move slower (less kinetic energy). Particles get closer together (less potential energy)

7 0
3 years ago
Read 2 more answers
a single 1,300 jk cargo car is rolling along a train track at 2.0 m/s when 400 kg of coal is dropped vertically into it. what is
tensa zangetsu [6.8K]

Answer:

1.53 m/s

Explanation:

Given:

Mass of the car (M) = 1300 kg

Mass of the coal (m) = 400 kg

Initial velocity of the car (U) = 2 m/s

Initial velocity of the coal (u) = 0 m/s (Since it is dropped)

When the coal is dropped into the car, then they move with same final velocity.

Let the final velocity be 'v' m/s.

For a closed system, the law of conservation of momentum holds true.

So, initial momentum is equal to final momentum of the car-coal system.

Initial momentum of the car = MU=1300\times 2=2600\ Ns

Initial momentum of the coal = mu=0\ Ns

Total initial momentum is the sum of the above two momentums.

So, total initial momentum = 2600 + 0 = 2600 Ns

Now, final momentum is given as the product of combined mass and final velocity. So,

Final momentum of the system = (M+m)v=(1300+400)v=1700v

Now, from law of conservation of momentum,

Initial momentum = Final momentum

2600=1700v\\\\v=\frac{2600}{1700}\\\\v=1.53\ m/s

Therefore, the final velocity of either of the two masses is same is equal to 1.53 m/s.

4 0
3 years ago
A motor is operating at 3450 RPM and is producing a torque of 32 lb-in. What is the output horsepower of the motor?
ra1l [238]

Answer:

11561W

Explanation:

6 0
3 years ago
A 1500 kg weather rocket accelerates upward at 10.0 m/s . It explodes 2.00 s after liftoff and breaks into two fragments, one tw
serious [3.7K]

20 m/s is the speed of the heavier fragment just after the explosion.

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = ma                   where, F = Force (Newton)

                                          m= mass

                                          a = acceleration

Given:

mass of rocket = M = 1500 kg

acceleration of rocket = a = 10 m/s²

elapsed time = t = 2.00 s

mass of lighter fragment = m₁ = m = 500 kg

mass of heavier fragment = m₂ = 2m = 1000 kg

maximum height of lighter fragment = h = 530 m

Let's calculate the final speed of the rocket just before the explosion:

v = u + at

v = 0 + 10(2)

v = 20 m/s

Then, we will calculate the height of the rocket just before the explosion:

h' = ut + \frac{1}{2}at^{2}

h' = 0 + \frac{1}{2} (10)(2.00)^{2}

h' =20m

The initial speed of lighter fragment just after the explosion:

v^{2}₁ = u^{2}₁ - 2gΔh

v^{2}₁ = u^{2}₁ - 2g (h - h')

0^{2} = u^{2}₁- 2(9.8) (530-20)

u^{2}₁=9996

u₁ =\sqrt{9996}  m/s

Using Conservation of Momentum Law :

M v=m₁ u₁ +  m₂u₂

1500 (20)= 500(\sqrt{9996} ) + 1000u₂

u₂ ≅ - 20 m/s

Learn more about Newton's law of motion here:

brainly.com/question/10454047

#SPJ4

7 0
1 year ago
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