You throw a ball into a box and close the lid. You hear the ball bouncing around inside as the ball’s energy changes from gravit
1 answer:
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Answer:
1.53 m/s
Explanation:
Given:
Mass of the car (M) = 1300 kg
Mass of the coal (m) = 400 kg
Initial velocity of the car (U) = 2 m/s
Initial velocity of the coal (u) = 0 m/s (Since it is dropped)
When the coal is dropped into the car, then they move with same final velocity.
Let the final velocity be 'v' m/s.
For a closed system, the law of conservation of momentum holds true.
So, initial momentum is equal to final momentum of the car-coal system.
Initial momentum of the car =
Initial momentum of the coal =
Total initial momentum is the sum of the above two momentums.
So, total initial momentum = 2600 + 0 = 2600 Ns
Now, final momentum is given as the product of combined mass and final velocity. So,
Final momentum of the system =
Now, from law of conservation of momentum,
Initial momentum = Final momentum
Therefore, the final velocity of either of the two masses is same is equal to 1.53 m/s.
Answer:
11561W
Explanation:
20 m/s is the speed of the heavier fragment just after the explosion.
Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
F = ma where, F = Force (Newton)
m= mass
a = acceleration
Given:
mass of rocket = M = 1500 kg
acceleration of rocket = a = 10 m/s²
elapsed time = t = 2.00 s
mass of lighter fragment = m₁ = m = 500 kg
mass of heavier fragment = m₂ = 2m = 1000 kg
maximum height of lighter fragment = h = 530 m
Let's calculate the final speed of the rocket just before the explosion:
v = u + at
v = 0 + 10(2)
v = 20 m/s
Then, we will calculate the height of the rocket just before the explosion:
The initial speed of lighter fragment just after the explosion:
₁
₁ -
Δ
₁
₁ -
₁
₁
₁
Using Conservation of Momentum Law :
₁
₁
₂
₂
₂
₂ ≅
Learn more about Newton's law of motion here:
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