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saveliy_v [14]
3 years ago
12

An element which forms an oxide that dissolves in water to form an acidic solution.

Chemistry
1 answer:
zzz [600]3 years ago
8 0

Answer:

An Alkaline solution should be the answer to that.

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A chemist needs 0.550 mol selenium for a reaction. What mass of selenium should a chemist use?
-BARSIC- [3]

Answer:

The chemist would require to use 43.43 grams.

Explanation:

In order to solve this problem we need to know<u> how much do 0.550 moles of selenium weigh</u>. To do that we use selenium's<em> molar mass </em>and multiply it by the given number of moles:

  • 0.550 mol * 78.96 g/mol = 43.43 g

The chemist would require to use 43.43 grams.

4 0
3 years ago
match the following items......(1. used in engines and rockets souring 2. a type of slow combustion respiration 3. a chemical ch
mezya [45]
1. Rapid combustion - <span>used in engines and rockets souring. Large amount of energy produced.
</span>2. R<span>espiration - </span><span>a type of slow combustion. Organic matter is transfered into energy and carbon dioxide.
3. Soaring - a chemical change. A</span>cidification of milk into soured milk.<span>
4. Oxidation - electron loss when combining with another element. Metals gave electrons to nonmetals and became cations.
5. C</span>alcium - element in bone which absorbs X-rays. Calcium increases the photoelectric effect<span> which increase absorption of X-rays.
6. P</span>hotosynthesis reaction in which the product is glucose. Plants produce glucose from carbon dioxide and water.
7 0
3 years ago
Read 2 more answers
1. Given the specific heat of lead is 0.129 J/g.C and that it takes 93.4J of energy to
zheka24 [161]

Answer: 40 grams

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since Q = 93.4J

M = ?

C = 0.129 J/g.C

Φ = 40.4°C - 22.3°C = 18.1°C

Then, Q = MCΦ

Make Mass, M the subject formula

M = Q/CΦ

M = (93.4J) / (0.129 J/g.C x 18.1°C)

M = 93.4J / 2.33J/g

M = 40 g

Thus, the mass of the lead is 40 grams

8 0
3 years ago
How many milligrams of a 20mg sample of cesium-137 remain after 60 years
andrey2020 [161]
Cs -137 has a half life of about 30 years. If 60 years pass, there is two half lives passed so 1/2 * 1/2= 1/4. Take 1/4 and multiply it with the mass given:
(1/4)*20mg=5mg left
5 0
3 years ago
-3 × 4=? ....................​
blagie [28]

Answer:

-12

Explanation:

a negative times a positive is negative

8 0
4 years ago
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