Your classmate's error about AB and DC being complimentary and parallel is that they misapplied the alternate angle property.
<h3>Why are AB and DC not parallel?</h3><h3 />
There isn't enough evidence presented in the diagram to say that AB and DC are parallel.
The evidence required would be proof that angle AWZ is equal to angle WZY.
Instead, all we have is that angle AWZ and angle XYC are equal which does not tell us what we need to know about AB and DC being parallel.
Find out more on properties of parallel lines at brainly.com/question/24607467
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.25
you can come to this conclusion by calculating 13/52
Answer:
Graph 1 because if you just do the Y coordinate its much easier.
27 - 1.5x ≤ 36
54 - 3x ≤ 72
54 - 72 ≤3x
-18 ≤ 3x
-6 ≤ x
x ≥ -6
<span>Put it in the form of y =mx +b, or in this instance, y> mx +b
move the (1/2) x to the right by adding it to both sides of the inequality
(1/3)y>(1/2)x +2
Multiply by 3 on both sides to get y by itself.
y>(3/2) x +6
This is a graph with y intercept of (0,6) and a moderate upward and to the right slope. Because it is > , the line on the graph will NOT be part of the solution.
The easiest way to find the side of the graph that the inequality satisfies is to use (0,0) and see if it works or doesn't work. In the original equation, 0-0>2 does NOT work, so the area where the inequality works is to the up and left of the graph, which should be a dotted line to show that the inequality is greater than only.
The point (6,-2) should work.
Test it. 6*(1/3)-(-2)*(1/2)>0 ; 2-(-1)=3, and 3>2 It does work.
The point (6,2) should not work
Test it. 6 *(1/3)-2(1/2)=2-1 ; 1 is NOT >2, so it does not work.
If the graph goes through the origin, then pick a point near the graph with a small x or y.</span>
