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FrozenT [24]
3 years ago
13

A diagonal aluminum alloy tension rod of diameter d and initial length l is used in a rectangular frame to prevent collapse. The

rod can safely support a tensile stress of sallow. If d 5 0.5 in, l 5 8 ft, and sallow 5 20 kpsi, determine how much the rod must be stretched to develop this allowable stress.
Engineering
1 answer:
Ksenya-84 [330]3 years ago
6 0

Answer:

\Delta L = 0.1883 inch

Explanation:

Given data:

d = 0.5 inch

L_i = 8 ft

\sigma_{allow} = 20  kpsi

we know that change in length is given as

\Delta L = \frac{PL}{AE}

              = \frac{P}{A}\times \frac{L}{E}

              = \sigma_{allow} \times \frac{L}{E}

modulus of elasticity E for aluminium alloy is 10.2 \times 10^6 psi = 10.2 \times 10^3 kpsi

\Delta L = \frac{20 \times 8}{10.2\times 10^3}

\Delta L = 0.01569 ft

\Delta L = 0.1883 inch

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