Answer:
5.70 m
Explanation:
3sₐ + sB = L
3∆sₐ = - ∆sB
3vₐ = -vB
3*3 = -vB
vB = -9 ms⁻²
T₁ + V₁ = T₂ + V₂
(0 + 0) + (0 + 0) = 1/2(20)(3)² + 1/2(30)(-9)² + 20*9.81*(sB/3) + 30*9.81* sB
0 = 90 + 1215 - 228.9sB
-1305 = - 228.9sB
sB = 1305/228.9 = 5.70 m
Explanation:
the 7th one answer is beacause mercury is bad at sharing electrons
the 8th one's answer is Rhodium
Answer:
irreversible head loss is 38.51 ft
mechanical power 6.55 hp
Explanation:
Given data:
Pump Power 12 hp = 8948.39 watt = 6600 lbs ft/sec
Q = 1.5 ft^3/s
Pump actually delivers 
Power that water gains

hence Power lost = 6600 - 2995.2 3604.8 lbs ft/sec = 6.55 hp
head loss
hl = 38.51 ft
Answer: the absolute static pressure in the gas cylinder is 82.23596 kPa
Explanation:
Given that;
patm = 79 kPa, h = 13 in of H₂O,
A sketch of the problem is uploaded along this answer.
Now
pA = patm + 13 in of H₂O ( h × density × g )
pA= 79 + (13 × 0.0254 × 9.8 × 1000/1000)
pA = 82.23596 kPa
the absolute static pressure in the gas cylinder is 82.23596 kPa