Answer:
The three types of lubrication occurred in the bearing are:
When the lubrication occur in the bearing it play an important role in the rolling life of bearing element. Basically, lubricant task is to reduced the friction.
1) Grease lubricant: Grease contain various type of additives which help in enhance the performance. It consist of oil where thickness are added as, this thickness improved the characteristics of grease.
2) Oil lubricant: This is used to reduced or minimized the friction and the lubricant oil is used to in those vehicles when they are motorized. Bearing lubricant oil is used to higher the speed capability.
3) Solid films: These are non fluid coating surface that are applied in the friction surface for prevention. It is used in very extreme situation where oil and grease types of lubricant does not work.
Answer:
maybe it's twang because of the blade tension
Answer:
//Convert any decimal number to binary number
//Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include <iostream>
using namespace std;
// Main Method declared here
int main()
{
int x;
cout<<"Enter any integer number: ";
cin>>x;
DecBin(x);
return 0;
}
// Here a function named DecBin is declared along with an integer variable, x
void DecBin(int x)
{
// Declare an array to store the resulting binary digits
int bindigit[32];
// counter for binary array
int kount = 0;
while (x > 0) {
// Store the remainder of each division in the declared array
bindigit[kount] = x % 2;
x = x / 2;
kount++;
}
// Loop to print the binary digits in reverse order
for (int j = i - 1; j >= 0; j--)
{
cout << bindigit[j];
}
}
// End of Program
Answer:
Plumbing using a one-way check valve to stop water flowing back on a pump when the pump shuts off.
Explanation:
Diodes are like check valves, keeping current from flowing both ways. Used to create d.c. out of a.c by rectification. Also to block flow if d.c. power like a battery is hooked up in reverse polarity.
Answer:
When water is surrounding T_s = 34.17 degree C
When air surrounding T_S = 1434.7 degree C
from above calculation we can conclude that air is less effective than water as heat transfer agent
Explanation:
Given data:
length = 300 mm
Outer diameter = 30 mm
Dissipated energy = 2 kw = 2000 w
Heat transfer coefficient IN WATER = 5000 W/m^2 K
Heat transfer coefficient in air = 50 W/m^2 K
we know that 
From newton law of coding we have
is surface temp.
T - temperature at surrounding
![P = hA(T_s - T_{\infity})[tex]\frac{P}{\pi hDL} = (T_s - T_{\infity})](https://tex.z-dn.net/?f=P%20%3D%20hA%28T_s%20-%20%20T_%7B%5Cinfity%7D%29%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7BP%7D%7B%5Cpi%20hDL%7D%20%3D%20%20%28T_s%20-%20%20T_%7B%5Cinfity%7D%29)
solving for[/tex] T_s [/tex] w have
When air is surrounding we have
from above calculation we can conclude that air is less effective than water as heat transfer agent
