Answer:
b) Vectors A and B are in the same direction.
Explanation:
To understand this problem we will say that vector A has a magnitude of 5 units and vector B a magnitude of 3 units. In the subtraction of vectors the initial parts of vectors always bind together. And the vector resulting from the subtraction is traced from the end of the second vector (B) to the end of the first vector (A).
The length of the resultant vector will be 5 - 3 = 2
In the attached image, we analyze case a), b), and d)
For a)
As we can see in the attached image the resultant vector has a length of 8 units.
For d)
As we can see in the attached image the resultant vector has a length of 5.83 units.
For b)
The resultant vector has a length of 2 units.
Therefore the case given in b) is true
Answer:
When an unbalanced force acts on a body the side with the greater force's dircetion makes the object move along its direction
Also to find the net force acting on the bofldy you can subtract the two force acting on the body
In case of balanced force the net force will always be 0
Answer:
Comets
Explanation:
The Kuiper Belt is a collection of trans-Neptunian objects that consist of comets and other dwarf planets, including Pluto.
Answer:
The value of the distance is 
.
Explanation:
The velocity of a particle(v) executing SHM is
where, 
is the angular frequency, 
is the amplitude of the oscillation and 
is the displacement of the particle at any instant of time.
The velocity of the particle will be maximum when the particle will cross its equilibrium position, i.e., 
.
The maximum velocity(
) is
Divide equation (1) by equation(2).
Given, 
and 
. Substitute these values in equation (3).
Answer:
E) is described by all of these
Explanation:
The magnetic force on a charged particle is expressed as:
F = qv * B = qvBsinθ
Where,
q = charge on particle
θ = angle between the magnetic field and the particle velocity.
v = velocity of the particle
B = magnitude of field vector
From here, we could denote that magnetic force, F depends on charge on particle, velocity of particle, magnitude of field vector.
The magnetic force on a charged particle is at right angles to both the velocity of the particle. The magnetic force and magnetic field in a charged particle are perpendicular to each other, the right hand rule is used to determine the direction of force.
The correct option is E.
