Answer:
A)
Cl + O3 --> ClO + O2
2ClO --> ClOOCl
ClOOCl --> 2 Cl + O2
B)
Cl2 + 4O3 -> 2 ClO + 5O2
Explanation:
Step 1: Chlorine atoms react with ozone (O3) to form chlorine monoxide and molecular oxygen
Cl + O3 --> ClO + O2
Step 2: Chlorine monoxide molecules combine to form ClOOCl gas
2ClO --> ClOOCl
Step 3: ClOOCl absorbs sunlight and breaks into chlorine atoms and molecular oxygen
ClOOCl --> 2 Cl + O2
B) Overall Balanced equation
Cl2 + 4O3 -> 2 ClO + 5O2
Answer: There are 4 monofluoro derivatives of methylcyclopentane. Only 1 derivative has flourine atom attached to a primary carbon.
Explanation: The compound methylcyclopentane has 1-primary carbon, 4- secondary carbons and 1-tertiary carbon.
1) Primary carbon (1°): In this the carbon atom is attached directly to only one carbon atom.
2) Secondary carbon (2°): In this the carbon is attached directly to two carbon atoms.
3) Tertiary Carbon (3°): In this the carbon is attached directly to three carbon atoms.
The monofluoro derivatives are shown in the image below.
Structure B is the only derivative which has fluorine attached to primary carbon atom.
The number of electrons shared between the atoms in a I₂ molecule is two (2).
Explanation:
An iodine atom has 53 electrons and its electron configuration is;
2. 8. 8. 18. 17
1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁵
Note that the outermost p shell has 5 electrons while it can accommodate a maximum of 6 for stable electron configuration. Therefore an Iodine atom needs one (1) electron to acquire nobility. Two Iodine atoms will, therefore, share two electrons (each from one of their p sub-shell ) by covalent bonds to form I₂
Learn More:
For more on electron configuration and nobility check out;
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The answer is catalytic converters.
