How many moles are in 7.5 g of C3H11NO3 (Vitamin B6)

Chemistry

1 answer:

Tju [1.3M]3 years ago

5 0

Answer:

7.5g Vitamin B6 => 0.069 mole Vitimin B6 (C₃H₁₁NO₃)

Explanation:

To convert gram value to a mole value, divide formula weight of substance of interest into gram-value given; that is, ...

moles = mass of substance (g) / formula weight (g/mol)

formula weight of B6 =>∑ 3C + 11H + 1N + 3O

= 3mol(12g/mol) + 11mol(1g/mol) + 1mol(14g/mol) + 3mol(16g/mol)

= 36g + 11g + 14g +48g = 109g/mol

given 7.5g of Vitamin B6 converted to moles V6

= 7.5g / 109g/mol = 0.069 mol Vitamin B6

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