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Anna35 [415]
3 years ago
6

Jenna is playing with her toy cars, which are both the same size. She pushes the red car with a strong push. She pushes the blue

car with a weak push. What should Jenna expect to observe?
Chemistry
1 answer:
Vikki [24]3 years ago
7 0

Answer:

red car will travel a much farther distance and at a faster speed as opposed to the blue car

Explanation:

Based on the information provided within the question Jenna can expect to observe that the red car will travel a much farther distance and at a faster speed as opposed to the blue car which will travel a shorter distance and at a lower speed. This is mainly because Jenna is applying an increased amount of force on the red car thus creating more acceleration and ultimately increasing the distance.

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Question 5
Dafna11 [192]

The mass percent of oxygen is 32.82%.

<h3>What is a noble gas?</h3>

A noble gas is member of group 18 in the periodic table. The members of this group are known not to be reactive and they do not easily form compounds. However, there have been few compounds of the members of group 18 that have been reported.

Let us now calculate the relative molecular mass of xenon tetraoxide.

Xe + 4 (O)

131 + 4(16) = 195

Given that the mass of oxygen in the compound is 64, the mass  percent of oxygen in xenon tetroxide is obtained from;

64/195 * 100/1

= 32.82%

Learn more about mass percent:brainly.com/question/5394922

#SPJ1

5 0
1 year ago
A chemist prepares a solution of silver(I) nitrate by measuring out of silver(I) nitrate into a volumetric flask and filling the
leva [86]

Answer:

3.33 M

Explanation:

It seems your question is incomplete, however, that same fragment has been found somewhere else in the web:

" <em>A chemist prepares a solution of silver nitrate (AgNO3) by measuring out 85.g of silver nitrate into a 150.mL volumetric flask and filling the flask to the mark with water.</em>

<em>Calculate the concentration in mol/L of the chemist's silver nitrate solution. Be sure your answer has the correct number of significant digits.</em> "

In this case, first we <u>calculate the moles of AgNO₃</u>, using its molecular weight:

  • 85.0 g AgNO₃ ÷ 169.87 g/mol = 0.500 mol AgNO₃

Then we<u> convert the 150 mL of the volumetric flask into L</u>:

  • 150 / 1000 = 0.150 L

Finally we <u>divide the moles by the volume</u>:

  • 0.500 mol AgNO₃ / 0.150 L = 3.33 M
4 0
3 years ago
NH3(aq) + HNO3(aq) → NH4NO3(aq) Calculate the volume of an acid (1.5 M HNO3) needed to neutralize the 1.5 M HNO3.
SCORPION-xisa [38]

Answer:

NH3(aq) + HNO3(aq) → NH4NO3(aq) Calculate the volume of an acid (1.5 M HNO3) needed to neutralize the 1.5 M HNO3.

Explanation:

8 0
3 years ago
The equation for the synthesis of ammonia is below. How many moles of H 2 are
kkurt [141]

Moles of H₂ are needed to produce 9.33 moles of NH₃ : 13.995

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

The reaction coefficient in a chemical equation shows the mole ratio of the reactants and products

Reaction for the synthesis of ammonia :

N₂+3H₂⇒2NH₃

moles of NH₃ = 9.33

From equation, mol ratio of H₂ : NH₃ = 3 : 2, so mol H₂ :

\tt =\dfrac{3}{2}\times 9.33\\\\=13.995

4 0
3 years ago
Which shows the rational expression written using the least common denominator?
Alexandra [31]

Answer:

The first one.

\frac{x + 1}{4x^{2} } and \frac{4(x + 1)}{4x^{2} }

Explanation:

When comparing two fractions with variables like this, it's important to get to the same denominator in order to compare apples with apples and then be able to do not only comparisons but also perform additions/subtractions.

Question is which denominator to use and how to reach it.

In this case, the question and the answer choices do the work for you.  The question asks which one is the LEAST common denominator, and the answers show denominators x² and 4x².  The smallest of these is x², however, we can't simplify the first fraction to get to the x² denominator, so we'll go for the 4x².

So, the first fraction has already the correct denominator (4x²), we just have to transform the second one.

We multiply it by 1, expressed in a different way.  Since we're multiplying by one, we're not affecting the value, just the way it looks.

Let's do it!, to get the denominator to go from x² to 4x², we need to multiply it by 4... so we'll multiply by 4/4 (which is 1, neutral for the multiplication).

\frac{x + 1}{x^{2} } * \frac{4}{4} = \frac{4(x + 1)}{4x^{2} }

And now you have both fractions on the same denominator, without having changed their value, just their looks

6 0
3 years ago
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