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Goshia [24]
3 years ago
7

Jordan needs to repeat the experiment but his teacher says that he needs to improve his design in his second experiment what sho

uld he do different
Chemistry
2 answers:
Margarita [4]3 years ago
8 0
Just add more detail in the second experiment explain every little thing.
Anon25 [30]3 years ago
4 0

Answer: A

Explanation:

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How many of the zeros in the measurement 0.050060 are significant
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I think 3 of them are its been 1 half years since ive done this i dont take chemistry anymore
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What is the role of neutrons in an atom??
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They're only found in the nucleus and play an important role in keeping the atom stable because they carry a negative charge to counteract the proton's positive charge. 
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3 years ago
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Which statements describe the law of conservation of charge? Check all that apply.
AlekseyPX
The statements in accordance with the law of conservation of charge are:
A. The total charge of the reactants and products must be equal
B. The net charge of an isolated system remains constant

Both of these statements follow the law of conservation of charge which states that charge may neither be created nor destroyed, due to which the total charge in an isolated system (one in which charge can not move in or out of) remains constant.
5 0
3 years ago
At what Celsius temperature does 0.750 mol of an ideal gas occupy a volume of 35.9 L at 114 kPa?
shepuryov [24]

382.85  Celsius is the temperature does 0.750 moles of an ideal gas occupy a volume of 35.9 L at 114 kPa.

Explanation:

Given data:

number of moles of the gas  = 0.75 moles

volume of the gas = 35.9 liters

pressure of the gas = 114 KPa or 1.125 atm

R = 0.0821 latm/moleK

temperature of the gas T = ?

The equation used to calculate temperature from above data is ideal gas law equation.

the equation is :

PV = nRT

T = \frac{PV}{nR}

Putting the values in the above rewritten equation:

T = \frac{1.125 X 35.9}{0.75 X 0.0821}

T = 655.9 K

To convert kelvin into celsius, formula used is

K = 273.15+ C

putting the values in the equation

C = 656 - 273.15

   = 382.85  Celsius

8 0
3 years ago
A chemist determined by measurements that 0.030 moles of barium participated in a chemical reaction. Calculate the mass of bariu
schepotkina [342]

Answer: 4.1 g of barium precipitated.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}

Given : moles of barium = 0.030

Molar mass of barium = 137 g/mol

0.030=\frac{x}{137}

x= 4.1 g

Thus there are 4.1 g of barium that precipitated.

3 0
3 years ago
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