Which of the following is true for a parallel circuit?
1 answer:
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The time interval for which the proton remains in the field is -
Δt = .
We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.
We have to determine time interval during which the proton is in the field.
<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>The magnitude of force on the charged particle moving in a uniform magnetic field is given by -
F = qvB sinθ
According to the question, we have -
Entering Velocity (v) = 20 i m/s
Magnetic field intensity (B) = 0.3 T
Leaving velocity (u) = - 20 j m/s
Now -
The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -
d = =
Since, the radius of circular path is not given, we will assume it R.
Therefore, time for which proton remained in the field is -
t =
Hence, the time interval for which the proton remains in the field is -
Δt =
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When you double capacitance and inductance, the new resonance frequency becomes f/2.
- Resonance frequency:
The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.
It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.
Xc = Xl
which gives the value for resonance frequency:
where;
f is the resonance frequency
L is the inductance
C is the capacitance
When you double capacitance and inductance, the new resonance frequency becomes;
Thus from above,
When you double capacitance and inductance, the new resonance frequency becomes f/2.
Learn more about resonance frequency here:
<u>brainly.com/question/13040523</u>
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