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steposvetlana [31]
3 years ago
10

Which of the following is true for a parallel circuit?

Physics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

  1. Will you show the some answers so I can help
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Pls help. This is about heat. I got the answer, just need the working
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Answer:

See below

Explanation:

You have to heat the calorimeter to 100 C  from 20 C

  this will take   .20 kg *    390 j /kg-C   *  80 C = <u>6240 j</u>

You have to heat the mass of water to boiling point (100 C ) from 20C

this will take    

    .50 kg * 4182 j/kg-C  * 80 = <u>167,280 j </u>

AND you have to add enough heat to boil off  .03 kg of water:

   .03 kg * (2260000 j/kg-C )  =<u> 67,800 j</u>

<u />

Power = joules / sec =  (6240 + 167280 + 67800) / 274.8 =<u> 878 watts </u>

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<u>Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....</u>

7 0
2 years ago
I need help plzzzz!!!!!!!!!!!!!!!!
elena-s [515]

Answer:

You were a freeloader of my questions, so I'll be one too.

4 0
3 years ago
Which statement is true for a car that first goes around a curve of radius r at a constant speed v, and then goes around the sam
sasho [114]
Centripetal force is equal to (mv^2)/r
The way I use to answer these question is to set every variable to 1
m=1
v=1
r=1
so centripetal force =1
then change the variable we're looking at
and since we're find when it's half we could either change it to 1/2 or 2, but 2 is easier to use
m=1
v=2
r=1
((1)×(2)^2)/1=4
So the velocity in the 1st part is half the velocity in the 2nd part and the centripetal force is 4× less
The answer is the centripetal force is 1/4 as big the second time around
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