Hope this helps!!!! Here is a diagram
Answer: 0.3
Explanation:
We know that
Ka = [H+] * [A-] / [HA]
And the acid is 15 % dissociated means that
[A-] / [HA] *100 = 15%
So
[A-] / [HA] = 0.15
Then we know that [H+] = [A-] = 2 molar
Replacing we have
Ka = 2 molar * 0.15 = 0.3
The question deals with isotopes and how their masses differ from their normal elemental counterparts.
Here, T represents tritium, which is an isotope of hydrogen with a mass of 3 amu. Similarly, the isotope of oxygen present is ¹⁷O, which means it has a mass of 17 amu.
To determine the mass of this molecule, we do the following calculation:
3 * 2 + 17 * 2
6 + 34
40
The mass of T₂¹⁷O₂ is 40 amu
<u>Answer:</u> The normality of unknown acid solution is 0.232 N
<u>Explanation:</u>
To calculate the normality of the unknown acid solution, we use the equation:
where,
are the normality and volume of the unknown acid solution
are the normality and volume of NaOH solution
We are given:
Putting values in above equation, we get:
Hence, the normality of unknown acid solution is 0.232 N